Diesel Cycle Efficiency Calculator

Find the ideal thermal efficiency of a diesel (compression-ignition) engine from its compression ratio and cutoff ratio.

🚛 Diesel Cycle Efficiency Calculator
Ideal Diesel cycle efficiency
As a fraction
Step-by-step working

🚛 What is the Diesel Cycle Efficiency Calculator?

This Diesel cycle efficiency calculator finds the ideal thermal efficiency of a diesel engine from η=1−(1/r^(γ−1))×(rc^γ−1)/(γ(rc−1)). Enter the compression ratio, cutoff ratio, and heat capacity ratio, and it returns the theoretical maximum efficiency.

With a compression ratio of 20 and a cutoff ratio of 2, this calculator gives about 64.68% ideal efficiency, a realistic figure for a diesel engine's much higher compression ratio compared to gasoline.

At the same compression ratio, the Diesel cycle is actually slightly less efficient than the Otto cycle, diesel engines gain their real-world advantage from running much higher compression ratios than are safe for gasoline engines.

This calculator is useful for thermodynamics and automotive engineering students studying compression-ignition engine cycles.

📐 Formula

η  =  1 − (1/rγ−1) × (rcγ−1)/(γ(rc−1))
r = compression ratio, rc = cutoff ratio, γ = heat capacity ratio
Example: r=20, rc=2, γ=1.4: η ≈ 64.68%.

📖 How to Use This Calculator

Steps

1
Enter the compression ratio.
2
Enter the cutoff ratio.
3
Enter the heat capacity ratio (γ).
4
Read the ideal Diesel cycle efficiency.

💡 Example Calculations

Example 1 - Typical diesel engine

1
r=20, rc=2, γ=1.4
2
η = 1 − (1/200.4)×(21.4−1)/(1.4×1)
3
η = 64.6782%
η = 64.6782%
Try this example →

Example 2 - Higher cutoff ratio (more fuel injected)

1
r=18, rc=2.5, γ=1.4
2
η = 1 − (1/180.4)×(2.51.4−1)/(1.4×1.5)
3
η = 60.9365%
η = 60.9365%
Try this example →

Example 3 - Lower cutoff ratio, lower compression

1
r=16, rc=1.8, γ=1.4
2
η = 1 − (1/160.4)×(1.81.4−1)/(1.4×0.8)
3
η = 62.3853%
η = 62.3853%
Try this example →

❓ Frequently Asked Questions

What is the Diesel cycle?+
The Diesel cycle is the idealized thermodynamic cycle used to model a compression-ignition (diesel) engine, where fuel is injected into hot, highly compressed air and ignites without a spark, with combustion modeled as occurring at constant pressure rather than constant volume.
What is the formula for Diesel cycle efficiency?+
η = 1 − (1/r^(γ−1)) × (rc^γ−1)/(γ(rc−1)), where r is the compression ratio, rc is the cutoff ratio, and γ is the heat capacity ratio of the working gas.
What is cutoff ratio?+
Cutoff ratio rc is the ratio of cylinder volume at the end of constant-pressure combustion to the volume at the start of combustion, it measures how much the piston moves while fuel is still being injected and burning.
Why do diesel engines use much higher compression ratios than gasoline engines?+
Diesel engines compress only air (not a fuel-air mixture), so they can safely use much higher compression ratios (typically 16-22) without risking the pre-ignition knock that limits gasoline (Otto cycle) engines to around 8-12.
Is the Diesel cycle more or less efficient than the Otto cycle at the same compression ratio?+
At the exact same compression ratio, the Diesel cycle is actually slightly less efficient than the Otto cycle, because constant-pressure combustion is inherently less thermodynamically efficient than constant-volume combustion. Diesel engines instead gain their real-world advantage by running much higher compression ratios than are safe for gasoline engines.
What happens to Diesel efficiency as the cutoff ratio approaches 1?+
As rc→1 (representing an infinitesimally short combustion period), the Diesel cycle efficiency formula approaches the Otto cycle efficiency formula exactly, since near-instantaneous combustion behaves like the Otto cycle's constant-volume assumption.
What is a typical ideal efficiency for a diesel engine?+
With a compression ratio of 20 and a cutoff ratio of 2 (representative values), the ideal Diesel cycle efficiency is about 64.7%, higher than a typical gasoline Otto cycle engine's ideal efficiency because of the diesel engine's much higher achievable compression ratio.
Do real diesel engines achieve their full ideal Diesel cycle efficiency?+
No, like all idealized thermodynamic cycles, the Diesel cycle assumes no friction, no heat loss, and instantaneous processes apart from the modeled combustion phase. Real diesel engines achieve considerably less than the ideal figure, though typically still more than a comparable real gasoline engine.
Why is combustion modeled as constant-pressure in the Diesel cycle?+
In a real diesel engine, fuel is injected gradually and burns progressively as the piston continues moving, roughly maintaining pressure during this phase, rather than burning nearly instantaneously (constant volume) as in a spark-ignited gasoline engine.
Does the cutoff ratio depend on engine load?+
Yes, cutoff ratio increases with more fuel injected per cycle (higher load), since more fuel means a longer constant-pressure combustion phase and more piston travel before cutoff, this is one reason diesel engine efficiency varies meaningfully with operating load.

What is the Diesel cycle?

The Diesel cycle is the idealized thermodynamic cycle used to model a compression-ignition (diesel) engine, where fuel is injected into hot, highly compressed air and ignites without a spark, with combustion modeled as occurring at constant pressure rather than constant volume.

What is the formula for Diesel cycle efficiency?

η = 1 − (1/r^(γ−1)) × (rc^γ−1)/(γ(rc−1)), where r is the compression ratio, rc is the cutoff ratio, and γ is the heat capacity ratio of the working gas.

What is cutoff ratio?

Cutoff ratio rc is the ratio of cylinder volume at the end of constant-pressure combustion to the volume at the start of combustion, it measures how much the piston moves while fuel is still being injected and burning.

Why do diesel engines use much higher compression ratios than gasoline engines?

Diesel engines compress only air (not a fuel-air mixture), so they can safely use much higher compression ratios (typically 16-22) without risking the pre-ignition knock that limits gasoline (Otto cycle) engines to around 8-12.

Is the Diesel cycle more or less efficient than the Otto cycle at the same compression ratio?

At the exact same compression ratio, the Diesel cycle is actually slightly less efficient than the Otto cycle, because constant-pressure combustion is inherently less thermodynamically efficient than constant-volume combustion. Diesel engines instead gain their real-world advantage by running much higher compression ratios than are safe for gasoline engines.

What happens to Diesel efficiency as the cutoff ratio approaches 1?

As rc→1 (representing an infinitesimally short combustion period), the Diesel cycle efficiency formula approaches the Otto cycle efficiency formula exactly, since near-instantaneous combustion behaves like the Otto cycle's constant-volume assumption.

What is a typical ideal efficiency for a diesel engine?

With a compression ratio of 20 and a cutoff ratio of 2 (representative values), the ideal Diesel cycle efficiency is about 64.7%, higher than a typical gasoline Otto cycle engine's ideal efficiency because of the diesel engine's much higher achievable compression ratio.

Do real diesel engines achieve their full ideal Diesel cycle efficiency?

No, like all idealized thermodynamic cycles, the Diesel cycle assumes no friction, no heat loss, and instantaneous processes apart from the modeled combustion phase. Real diesel engines achieve considerably less than the ideal figure, though typically still more than a comparable real gasoline engine.

Why is combustion modeled as constant-pressure in the Diesel cycle?

In a real diesel engine, fuel is injected gradually and burns progressively as the piston continues moving, roughly maintaining pressure during this phase, rather than burning nearly instantaneously (constant volume) as in a spark-ignited gasoline engine.

Does the cutoff ratio depend on engine load?

Yes, cutoff ratio increases with more fuel injected per cycle (higher load), since more fuel means a longer constant-pressure combustion phase and more piston travel before cutoff, this is one reason diesel engine efficiency varies meaningfully with operating load.