Parity and Selection Rule Checker

Classify an atomic transition as E1, M1, or E2 from the parity and Δl of the initial and final states.

🪞 Parity and Selection Rule Checker
Classification
Initial parity
Final parity
Δl
Step-by-step working

🪞 What is the Parity and Selection Rule Checker?

This parity and selection rule checker classifies an atomic transition by which type of electromagnetic multipole radiation, electric dipole (E1), magnetic dipole (M1), or electric quadrupole (E2), can connect two quantum states. Enter the initial and final n and l, and it returns the parity of each state and the transition classification.

Every state's parity is exactly (-1)^l: even for s and d orbitals, odd for p and f orbitals. Electric dipole radiation, the strongest and fastest mechanism, requires a parity change (the Laporte rule) and |Δl|=1. When that fails, the transition may still proceed via the much weaker magnetic dipole (Δl=0, no parity change) or electric quadrupole (Δl=0 or ±2, no parity change) mechanisms.

This classification directly explains the "forbidden lines" seen in astrophysical spectra: transitions that are E1-forbidden can still occur via M1 or E2 radiation, just far more slowly, and become visible only in extremely low-density environments like nebulae, where atoms survive long enough between collisions to emit them.

This calculator is useful for physics and astronomy students studying atomic transitions and spectroscopy, and anyone curious why some spectral lines are labeled with square brackets like [O III].

📐 Formula

parity = (−1)l
E1: |Δl| = 1, parity must change
M1: Δl = 0, parity unchanged
E2: Δl = 0 or ±2, parity unchanged
Example: l=1 (odd) → l=0 (even): parity changes, Δl=−1 ⇒ E1 allowed.

📖 How to Use This Calculator

Steps

1
Enter the initial state, n₁ and l₁.
2
Enter the final state, n₂ and l₂.
3
Read the classification, E1, M1/E2 only, E2 only, or forbidden to all three.

💡 Example Calculations

Example 1 - 2p → 1s (E1 allowed)

1
Initial: n=2, l=1 (p, odd parity). Final: n=1, l=0 (s, even parity)
2
Parity changes (odd → even), Δl = −1
3
Classification: E1, dominant allowed transition
Classification: E1 (electric dipole)
Try this example →

Example 2 - 3p → 2p (M1/E2 only, E1 forbidden)

1
Initial: n=3, l=1 (p, odd parity). Final: n=2, l=1 (p, odd parity)
2
Parity unchanged (odd → odd), Δl = 0
3
Classification: M1/E2 only, E1 fails the parity-change requirement
Classification: M1 / E2 only
Try this example →

Example 3 - 3d → 1s (E2 only)

1
Initial: n=3, l=2 (d, even parity). Final: n=1, l=0 (s, even parity)
2
Parity unchanged (even → even), Δl = −2
3
Classification: E2 only, both E1 and M1 fail
Classification: E2 (electric quadrupole) only
Try this example →

❓ Frequently Asked Questions

What is parity in quantum mechanics?+
Parity describes how a wavefunction behaves under spatial inversion (x → -x). A state is called even parity if it is unchanged by inversion, and odd parity if it flips sign. For a hydrogen-like orbital, the parity is exactly (-1)^l, so s and d orbitals (l=0, 2) are even, while p and f orbitals (l=1, 3) are odd.
What is the Laporte rule?+
The Laporte rule states that electric dipole (E1) transitions can only connect states of opposite parity, equivalently, |Δl| must be odd (in practice, exactly 1 for a single-electron transition). It follows directly from the electric dipole operator (proportional to position x) having odd parity itself.
What makes a transition 'forbidden'?+
A transition is 'forbidden' relative to a specific radiation mechanism when the corresponding transition matrix element is exactly zero by symmetry. E1-forbidden transitions can often still occur through weaker mechanisms, magnetic dipole (M1) or electric quadrupole (E2) radiation, which have different parity and Δl requirements and are typically thousands to millions of times slower.
What are magnetic dipole (M1) and electric quadrupole (E2) transitions?+
M1 transitions arise from the interaction of the atom's magnetic moment with the oscillating magnetic field of light, and require Δl = 0 with no parity change. E2 transitions arise from a higher-order term in the light-matter interaction and require Δl = 0 or ±2, also with no parity change. Both are much weaker than E1 because they involve smaller physical couplings, but they are not literally forbidden.
Why are 'forbidden lines' visible in nebulae but not in a lab?+
In a dense lab gas or solid, an excited atom is knocked into a different state by a collision long before it has a chance to decay via a slow M1 or E2 transition. In the extremely tenuous gas of a nebula, densities are so low that collisions are rare, giving atoms enough time (seconds to hours) to eventually emit the E1-forbidden line, which then becomes a bright, diagnostic feature of the nebula's spectrum.
What is a famous example of an astrophysical forbidden line?+
The green [O III] line at 500.7 nm, denoted with square brackets to indicate it is forbidden, comes from an M1/E2 transition between fine-structure levels of doubly-ionized oxygen with the same orbital configuration (Δl=0). It is one of the strongest lines in many planetary nebulae and was originally mistaken for a new element, 'nebulium', before its true origin was understood.
Why does E2 also allow Δl = 0, not just ±2?+
The electric quadrupole operator contains terms proportional to both x² (which connects states differing by 0 or 2 units of angular momentum) unlike the dipole operator's single power of x. This is why E2 transitions can connect states of the same l (as long as other quantum numbers like m or J differ) in addition to states two units apart.
Does this calculator account for total angular momentum J?+
No, it is deliberately scoped to the parity and Δl part of the selection rules for a single active electron's orbital quantum number, the first level of detail taught in most courses. Real multi-electron atoms have additional ΔJ selection rules (0, ±1 for E1/M1, 0/±1/±2 for E2, always excluding J=0 to J=0) that this calculator does not check.
Can Δl = 0 transitions ever be E1-allowed?+
No. Since parity is (-1)^l, Δl = 0 always means the parity stays the same, and E1 transitions strictly require a parity change (the Laporte rule). A Δl = 0 transition can only proceed via M1 or E2 radiation, never E1, regardless of any other quantum numbers.
What happens if |Δl| is 3 or more?+
A transition with |Δl| ≥ 3 is forbidden to electric dipole, magnetic dipole, and electric quadrupole radiation alike, since none of their selection rules permit such a large jump in orbital angular momentum for a single active electron. Higher multipole orders (M3, E4, and so on) could in principle connect such states, but these are vanishingly weak and rarely relevant.

What is parity in quantum mechanics?

Parity describes how a wavefunction behaves under spatial inversion (x → -x). A state is called even parity if it is unchanged by inversion, and odd parity if it flips sign. For a hydrogen-like orbital, the parity is exactly (-1)^l, so s and d orbitals (l=0, 2) are even, while p and f orbitals (l=1, 3) are odd.

What is the Laporte rule?

The Laporte rule states that electric dipole (E1) transitions can only connect states of opposite parity, equivalently, |Δl| must be odd (in practice, exactly 1 for a single-electron transition). It follows directly from the electric dipole operator (proportional to position x) having odd parity itself.

What makes a transition 'forbidden'?

A transition is 'forbidden' relative to a specific radiation mechanism when the corresponding transition matrix element is exactly zero by symmetry. E1-forbidden transitions can often still occur through weaker mechanisms, magnetic dipole (M1) or electric quadrupole (E2) radiation, which have different parity and Δl requirements and are typically thousands to millions of times slower.

What are magnetic dipole (M1) and electric quadrupole (E2) transitions?

M1 transitions arise from the interaction of the atom's magnetic moment with the oscillating magnetic field of light, and require Δl = 0 with no parity change. E2 transitions arise from a higher-order term in the light-matter interaction and require Δl = 0 or ±2, also with no parity change. Both are much weaker than E1 because they involve smaller physical couplings, but they are not literally forbidden.

Why are 'forbidden lines' visible in nebulae but not in a lab?

In a dense lab gas or solid, an excited atom is knocked into a different state by a collision long before it has a chance to decay via a slow M1 or E2 transition. In the extremely tenuous gas of a nebula, densities are so low that collisions are rare, giving atoms enough time (seconds to hours) to eventually emit the E1-forbidden line, which then becomes a bright, diagnostic feature of the nebula's spectrum.

What is a famous example of an astrophysical forbidden line?

The green [O III] line at 500.7 nm, denoted with square brackets to indicate it is forbidden, comes from an M1/E2 transition between fine-structure levels of doubly-ionized oxygen with the same orbital configuration (Δl=0). It is one of the strongest lines in many planetary nebulae and was originally mistaken for a new element, 'nebulium', before its true origin was understood.

Why does E2 also allow Δl = 0, not just ±2?

The electric quadrupole operator contains terms proportional to both x² (which connects states differing by 0 or 2 units of angular momentum) unlike the dipole operator's single power of x. This is why E2 transitions can connect states of the same l (as long as other quantum numbers like m or J differ) in addition to states two units apart.

Does this calculator account for total angular momentum J?

No, it is deliberately scoped to the parity and Δl part of the selection rules for a single active electron's orbital quantum number, the first level of detail taught in most courses. Real multi-electron atoms have additional ΔJ selection rules (0, ±1 for E1/M1, 0/±1/±2 for E2, always excluding J=0 to J=0) that this calculator does not check.

Can Δl = 0 transitions ever be E1-allowed?

No. Since parity is (-1)^l, Δl = 0 always means the parity stays the same, and E1 transitions strictly require a parity change (the Laporte rule). A Δl = 0 transition can only proceed via M1 or E2 radiation, never E1, regardless of any other quantum numbers.

What happens if |Δl| is 3 or more?

A transition with |Δl| ≥ 3 is forbidden to electric dipole, magnetic dipole, and electric quadrupole radiation alike, since none of their selection rules permit such a large jump in orbital angular momentum for a single active electron. Higher multipole orders (M3, E4, and so on) could in principle connect such states, but these are vanishingly weak and rarely relevant.