de Broglie Wavelength Calculator

Find the matter wavelength of a particle from its mass and speed using lambda = h divided by momentum.

⚛️ de Broglie Wavelength Calculator
kg
m/s
Wavelength
In nanometres
In picometres
Momentum
Step-by-step working

⚛️ What is the de Broglie Wavelength Calculator?

The de Broglie wavelength calculator finds the wavelength of the matter wave associated with a moving particle. In 1924 Louis de Broglie proposed that every particle, not just light, has a wavelength set by its momentum, given by lambda = h divided by m times v. This calculator applies that relation to any particle you specify.

Students and physicists use it to see why the quantum world behaves as it does. The electron's wavelength, close to the spacing between atoms in a crystal, explains electron diffraction and the resolving power of electron microscopes. Working out that a neutron at reactor speeds has a wavelength near atomic dimensions shows why neutron scattering probes material structure. Comparing an electron's wavelength with a baseball's, which is smaller than a nucleus, shows exactly why wave behaviour is invisible in everyday life.

The essential idea is the inverse relationship with momentum. A larger momentum, from more mass or more speed, means a shorter wavelength. Because Planck's constant is so tiny (6.626 x 10^-34 joule-seconds), only very light and fast particles end up with wavelengths large enough to matter. A frequent confusion is mixing up this matter wavelength with a photon's wavelength: photons have no mass and use energy rather than m times v, so the formula is different even though both involve Planck's constant.

This tool is useful because it handles the awkward scientific notation and unit conversions for you. Pick a particle or enter a mass, give the speed, and read the wavelength in metres, nanometres, and picometres along with the momentum, with the working shown so the calculation is transparent.

📐 Formula

λ  =  h ÷ (m × v)
λ = de Broglie wavelength (metres)
h = Planck's constant = 6.62607 × 10-34 J·s
m = particle mass (kilograms)
v = particle speed (metres per second)
Momentum p = m × v, so λ = h ÷ p
Example: Electron (9.109 × 10-31 kg) at 1 × 106 m/s: λ = 7.27 × 10-10 m = 0.727 nm.

📖 How to Use This Calculator

Steps

1
Choose a particle (electron, proton, neutron) to fill the mass, or pick custom.
2
Enter the speed in metres per second.
3
Read the wavelength in metres, nanometres, and picometres, plus the momentum.

💡 Example Calculations

Example 1 - Electron at a million metres per second

1
m = 9.109 × 10-31 kg, v = 1 × 106 m/s
2
p = m v = 9.109 × 10-25 kg·m/s
3
λ = h ÷ p = 7.27 × 10-10 m = 0.727 nm
Wavelength = 7.27 × 10⁻¹⁰ m (0.727 nm)
Try this example →

Example 2 - Proton at 500 km per second

1
m = 1.673 × 10-27 kg, v = 5 × 105 m/s
2
p = m v = 8.363 × 10-22 kg·m/s
3
λ = h ÷ p = 7.92 × 10-13 m = 0.79 pm
Wavelength = 7.92 × 10⁻¹³ m (0.79 pm)
Try this example →

Example 3 - Baseball (why big objects have no waves)

1
m = 0.145 kg, v = 40 m/s
2
p = m v = 5.8 kg·m/s
3
λ = h ÷ p = 1.14 × 10-34 m, undetectably small
Wavelength = 1.14 × 10⁻³⁴ m
Try this example →

❓ Frequently Asked Questions

What is the de Broglie wavelength?+
It is the wavelength associated with a moving particle, given by lambda = h / (m v), where h is Planck's constant, m is mass, and v is speed. Louis de Broglie proposed that all matter has wave properties. For an electron moving at a million metres per second, the wavelength is about 0.73 nanometres.
How do you calculate the de Broglie wavelength?+
Multiply the particle's mass by its speed to get the momentum, then divide Planck's constant (6.626 x 10^-34 J.s) by that momentum. For an electron (9.109 x 10^-31 kg) at 1 x 10^6 m/s, momentum is 9.109 x 10^-25 kg.m/s, so lambda = 6.626 x 10^-34 / 9.109 x 10^-25 = 7.27 x 10^-10 m.
Why don't everyday objects show wave behaviour?+
Because their de Broglie wavelength is unimaginably small. A 0.145 kg baseball at 40 m/s has a wavelength of about 1 x 10^-34 metres, far smaller than an atomic nucleus, so no experiment can detect its wave nature. Only very light, fast particles like electrons have measurable wavelengths.
What is the de Broglie wavelength of an electron?+
It depends on the electron's speed. At 1 x 10^6 m/s the wavelength is about 0.73 nanometres, and at higher speeds it is shorter. This wavelength is close to atomic spacings, which is why electron beams diffract from crystals and why electron microscopes can resolve atomic detail.
How does momentum affect the de Broglie wavelength?+
The wavelength is inversely proportional to momentum: lambda = h / p. Doubling the momentum, by doubling either the mass or the speed, halves the wavelength. This is why heavy or fast particles have very short matter wavelengths and light, slow ones have longer wavelengths.
Can I calculate the de Broglie wavelength from kinetic energy?+
Yes. For a non-relativistic particle, momentum p equals the square root of 2 m KE, so lambda = h / sqrt(2 m KE). This calculator uses mass and speed directly; if you have kinetic energy, first find the speed from KE = half m v squared, then enter it.
What units should I use?+
Use SI units: mass in kilograms and speed in metres per second. Planck's constant is in joule-seconds, so the wavelength comes out in metres. This calculator also converts the result to nanometres and picometres, which are more convenient at the atomic scale.
Is the de Broglie wavelength the same as the photon wavelength?+
No. The de Broglie wavelength applies to particles with mass and uses their momentum m v. A photon has no mass, and its wavelength relates to its energy by lambda = h c / E. Both use Planck's constant, but the formulas differ because photons always travel at the speed of light.
Who discovered that matter has a wavelength?+
Louis de Broglie proposed the idea in his 1924 doctoral thesis, extending the wave-particle duality of light to all matter. It was confirmed in 1927 when Davisson and Germer observed electron diffraction from a nickel crystal. De Broglie received the 1929 Nobel Prize in Physics for the discovery.
Why do electron microscopes use electrons instead of light?+
Resolution is limited by wavelength, and electrons can have wavelengths thousands of times shorter than visible light. A fast electron's de Broglie wavelength is a fraction of a nanometre, near atomic spacing, so an electron microscope resolves detail far finer than any optical microscope, which is limited to a few hundred nanometres.

What is the de Broglie wavelength?

It is the wavelength associated with a moving particle, given by lambda = h / (m v), where h is Planck's constant, m is mass, and v is speed. Louis de Broglie proposed that all matter has wave properties. For an electron moving at a million metres per second, the wavelength is about 0.73 nanometres.

How do you calculate the de Broglie wavelength?

Multiply the particle's mass by its speed to get the momentum, then divide Planck's constant (6.626 x 10^-34 J.s) by that momentum. For an electron (9.109 x 10^-31 kg) at 1 x 10^6 m/s, momentum is 9.109 x 10^-25 kg.m/s, so lambda = 6.626 x 10^-34 / 9.109 x 10^-25 = 7.27 x 10^-10 m.

Why don't everyday objects show wave behaviour?

Because their de Broglie wavelength is unimaginably small. A 0.145 kg baseball at 40 m/s has a wavelength of about 1 x 10^-34 metres, far smaller than an atomic nucleus, so no experiment can detect its wave nature. Only very light, fast particles like electrons have measurable wavelengths.

What is the de Broglie wavelength of an electron?

It depends on the electron's speed. At 1 x 10^6 m/s the wavelength is about 0.73 nanometres, and at higher speeds it is shorter. This wavelength is close to atomic spacings, which is why electron beams diffract from crystals and why electron microscopes can resolve atomic detail.

How does momentum affect the de Broglie wavelength?

The wavelength is inversely proportional to momentum: lambda = h / p. Doubling the momentum, by doubling either the mass or the speed, halves the wavelength. This is why heavy or fast particles have very short matter wavelengths and light, slow ones have longer wavelengths.

Can I calculate the de Broglie wavelength from kinetic energy?

Yes. For a non-relativistic particle, momentum p equals the square root of 2 m KE, so lambda = h / sqrt(2 m KE). This calculator uses mass and speed directly; if you have kinetic energy, first find the speed from KE = half m v squared, then enter it.

What units should I use?

Use SI units: mass in kilograms and speed in metres per second. Planck's constant is in joule-seconds, so the wavelength comes out in metres. This calculator also converts the result to nanometres and picometres, which are more convenient at the atomic scale.

Is the de Broglie wavelength the same as the photon wavelength?

No. The de Broglie wavelength applies to particles with mass and uses their momentum m v. A photon has no mass, and its wavelength relates to its energy by lambda = h c / E. Both use Planck's constant, but the formulas differ because photons always travel at the speed of light.