Lawson Criterion Calculator

Find the minimum density × confinement time a D-T plasma needs at a given temperature to reach ignition, and see how your plasma compares.

🔆 Lawson Criterion Calculator
keV
m⁻³
s
Required (nτE)min
Actual nτE
% of threshold
Step-by-step working

🔆 What is the Lawson Criterion Calculator?

This Lawson criterion calculator finds the minimum plasma density times energy confinement time (nτ_E) needed for a deuterium-tritium plasma's fusion self-heating to balance its energy losses at a given temperature, then compares it against your actual n × τ_E. Enter the temperature, ion density, and confinement time, and it returns the required threshold, your actual value, and the percentage of that threshold reached.

The Lawson criterion, first derived by John Lawson in 1955, is the foundational energy-balance condition behind every magnetic confinement fusion reactor design, from early tokamaks to ITER. It comes from setting the fusion charged-particle heating power density equal to the rate at which thermal energy leaks out of the plasma, 3nT/τ_E.

Unlike the simpler fusion triple product, which is compared against one fixed round-number benchmark, this calculator computes a threshold that genuinely varies with temperature, using the standard ⟨σv⟩ ≈ 1.1×10⁻²⁴T² reactivity approximation that is accurate over the 10-20 keV range most fusion experiments target.

This calculator is useful for plasma physics and fusion engineering students, and for anyone comparing real or hypothetical tokamak operating points against the physical bar a D-T plasma must clear to reach ignition.

📐 Formula

E ≥ 12T ÷ (⟨σv⟩ Ech)
T = plasma temperature (keV), ⟨σv⟩ = fusion reactivity ≈ 1.1×10⁻²⁴T² m³/s (10-20 keV)
Ech = 3.5 MeV, the D-T alpha particle's charged-particle energy share
Derived from equating fusion self-heating power to the thermal loss rate 3nT÷τE
Example: at T=15 keV, (nτE)min ≈ 2.078×10²⁰ s/m³.

📖 How to Use This Calculator

Steps

1
Enter the temperature in keV, ideally between 10 and 20 keV where the approximation is most accurate.
2
Enter density and confinement time, ion density in particles per cubic metre and energy confinement time in seconds.
3
Read the required and actual nτE, and compare the percentage of threshold reached.

💡 Example Calculations

Example 1 - ITER-class target parameters

1
T=15 keV, n=10²⁰ m⁻³, τE=3 s
2
(nτE)min = 2.0779 × 1020 s/m³
3
Actual nτE = 3.0000 × 1020 s/m³, 144.38% of threshold, criterion met
144.38% of threshold, criterion met
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Example 2 - JET-class D-T record attempt

1
T=12 keV, n=4×10⁹ m⁻³, τE=0.85 s
2
(nτE)min = 2.5974 × 1020 s/m³
3
Actual nτE = 3.4000 × 1019 s/m³, only 13.09% of threshold, criterion not met
13.09% of threshold, criterion not met
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Example 3 - Small early-generation tokamak

1
T=10 keV, n=2×10⁹ m⁻³, τE=0.1 s
2
(nτE)min = 3.1169 × 1020 s/m³
3
Actual nτE = 2.0000 × 1018 s/m³, only 0.64% of threshold, illustrating decades of progress needed
0.64% of threshold, criterion not met
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❓ Frequently Asked Questions

What is the Lawson criterion?+
The Lawson criterion is the minimum value of the product of plasma density (n) and energy confinement time (τ_E) needed for a fusion reaction's self-heating power to balance the energy lost from the plasma, first derived by John Lawson in 1955. It sets the practical bar every magnetic confinement fusion device must clear.
What is the formula for the Lawson criterion?+
nτ_E ≥ 12T / (⟨σv⟩E_ch), where T is temperature, ⟨σv⟩ is the fusion reactivity (a function of T), and E_ch is the charged-particle fusion energy (3.5 MeV for D-T, the alpha particle's share). This comes from setting fusion charged-particle heating power equal to the thermal energy loss rate 3nT/τ_E.
Why does this calculator use ⟨σv⟩ ≈ 1.1×10⁻²⁴T² instead of an exact value?+
The exact D-T reactivity ⟨σv⟩(T) has no closed-form expression, only numerical fits to measured cross-sections. Over the practically relevant 10-20 keV range, ⟨σv⟩ ≈ 1.1×10⁻²⁴T² (T in keV, result in m³/s) is a well-known and widely cited approximation that keeps the criterion in exact closed form.
Why is only 3.5 MeV used instead of the full 17.6 MeV D-T fusion energy?+
Each D-T reaction releases 17.6 MeV split between an alpha particle (3.5 MeV) and a neutron (14.1 MeV). The neutron is uncharged and escapes the magnetic field entirely, carrying its energy out of the plasma, so only the alpha's 3.5 MeV can heat the plasma and help sustain the reaction.
What does the percentage of threshold mean?+
It is your entered nτ_E divided by the minimum required nτ_E at the given temperature, expressed as a percentage. 100% or higher means the idealized Lawson criterion is satisfied at that operating point, below 100% means losses still exceed fusion self-heating.
How is the Lawson criterion different from the fusion triple product?+
The fusion triple product nTτ_E is compared against one fixed round-number benchmark (roughly 3×10²¹ m⁻³·keV·s) regardless of temperature. The Lawson criterion computes an nτ_E threshold that explicitly varies with temperature through ⟨σv⟩(T), giving a more physically grounded, temperature-specific target. See the related Fusion Triple Product Calculator for the simpler comparison.
Does a lower temperature always need a smaller nτ_E?+
Within the 10-20 keV range covered by this calculator's ⟨σv⟩ ≈ 1.1×10⁻²⁴T² approximation, the required nτ_E actually decreases as T increases, since reactivity grows faster than the linear T term in the numerator. Outside this range the real reactivity curve flattens and eventually falls, so the required nτ_E rises again at both very low and very high temperatures, a detail this simplified model does not capture.
What confinement time do real tokamaks achieve?+
Energy confinement times in present-day tokamaks typically range from tens of milliseconds in small devices to a few seconds in the largest machines like JET, generally too short combined with achievable densities to fully satisfy the Lawson criterion, which is exactly why ITER is being built at a much larger scale.
Is the Lawson criterion the same for every fusion fuel?+
No. Different fuel combinations (D-T, D-D, D-He3) have very different reactivity curves ⟨σv⟩(T) and charged-particle energy fractions, so each has its own Lawson criterion curve. D-T has by far the most favorable (lowest) Lawson criterion of any practical fusion fuel, which is why it is the near-term reactor fuel of choice.
How does energy confinement time get measured experimentally?+
τ_E is typically inferred from the ratio of the plasma's total stored thermal energy to the heating power needed to sustain it in steady state, τ_E = W/P_heat, a standard diagnostic computed from measured plasma parameters rather than a directly observed single quantity.
Why does the criterion involve n times τ_E rather than n and τ_E separately?+
The energy balance that produces the criterion, fusion heating power equal to the thermal energy loss rate, naturally reduces to a condition on the single combined quantity nτ_E, since a lower density can always be compensated by a proportionally longer confinement time (or vice versa) without changing whether the self-heating condition is met.

What is the Lawson criterion?

The Lawson criterion is the minimum value of the product of plasma density (n) and energy confinement time (τ_E) needed for a fusion reaction's self-heating power to balance the energy lost from the plasma, first derived by John Lawson in 1955. It sets the practical bar every magnetic confinement fusion device must clear.

What is the formula for the Lawson criterion?

nτ_E ≥ 12T / (⟨σv⟩E_ch), where T is temperature, ⟨σv⟩ is the fusion reactivity (a function of T), and E_ch is the charged-particle fusion energy (3.5 MeV for D-T, the alpha particle's share). This comes from setting fusion charged-particle heating power equal to the thermal energy loss rate 3nT/τ_E.

Why does this calculator use ⟨σv⟩ ≈ 1.1×10⁻²⁴T² instead of an exact value?

The exact D-T reactivity ⟨σv⟩(T) has no closed-form expression, only numerical fits to measured cross-sections. Over the practically relevant 10-20 keV range, ⟨σv⟩ ≈ 1.1×10⁻²⁴T² (T in keV, result in m³/s) is a well-known and widely cited approximation that keeps the criterion in exact closed form.

Why is only 3.5 MeV used instead of the full 17.6 MeV D-T fusion energy?

Each D-T reaction releases 17.6 MeV split between an alpha particle (3.5 MeV) and a neutron (14.1 MeV). The neutron is uncharged and escapes the magnetic field entirely, carrying its energy out of the plasma, so only the alpha's 3.5 MeV can heat the plasma and help sustain the reaction.

What does the percentage of threshold mean?

It is your entered nτ_E divided by the minimum required nτ_E at the given temperature, expressed as a percentage. 100% or higher means the idealized Lawson criterion is satisfied at that operating point; below 100% means losses still exceed fusion self-heating.

How is the Lawson criterion different from the fusion triple product?

The fusion triple product nTτ_E is compared against one fixed round-number benchmark (roughly 3×10²¹ m⁻³·keV·s) regardless of temperature. The Lawson criterion computes an nτ_E threshold that explicitly varies with temperature through ⟨σv⟩(T), giving a more physically grounded, temperature-specific target. See the related Fusion Triple Product Calculator for the simpler comparison.

Does a lower temperature always need a smaller nτ_E?

Within the 10-20 keV range covered by this calculator's ⟨σv⟩ ≈ 1.1×10⁻²⁴T² approximation, the required nτ_E actually decreases as T increases, since reactivity grows faster than the linear T term in the numerator. Outside this range the real reactivity curve flattens and eventually falls, so the required nτ_E rises again at both very low and very high temperatures, a detail this simplified model does not capture.

What confinement time do real tokamaks achieve?

Energy confinement times in present-day tokamaks typically range from tens of milliseconds in small devices to a few seconds in the largest machines like JET, generally too short combined with achievable densities to fully satisfy the Lawson criterion, which is exactly why ITER is being built at a much larger scale.

Is the Lawson criterion the same for every fusion fuel?

No. Different fuel combinations (D-T, D-D, D-He3) have very different reactivity curves ⟨σv⟩(T) and charged-particle energy fractions, so each has its own Lawson criterion curve. D-T has by far the most favorable (lowest) Lawson criterion of any practical fusion fuel, which is why it is the near-term reactor fuel of choice.

How does energy confinement time get measured experimentally?

τ_E is typically inferred from the ratio of the plasma's total stored thermal energy to the heating power needed to sustain it in steady state, τ_E = W/P_heat, a standard diagnostic computed from measured plasma parameters rather than a directly observed single quantity.

Why does the criterion involve n times τ_E rather than n and τ_E separately?

The energy balance that produces the criterion, fusion heating power equal to the thermal energy loss rate, naturally reduces to a condition on the single combined quantity nτ_E, since a lower density can always be compensated by a proportionally longer confinement time (or vice versa) without changing whether the self-heating condition is met.