Magnitude of Acceleration Calculator

Find the size and direction of an acceleration vector in 2D or 3D, from its components or from the change in velocity over a time interval.

🧭 Magnitude of Acceleration Calculator
Dimensions
Acceleration x component (ax)
m/s²
-5050
Acceleration y component (ay)
m/s²
-5050
Acceleration z component (az)
m/s²
-5050
Initial velocity v1, x component
m/s
Initial velocity v1, y component
m/s
Initial velocity v1, z component
m/s
Final velocity v2, x component
m/s
Final velocity v2, y component
m/s
Final velocity v2, z component
m/s
Time interval (Δt)
s
0.160
Magnitude |a|
—
In g
—
In ft/s²
—
xy-plane part
—
Angle (0 to 360)
—
Angle (signed)
—
Elevation above xy
—
cos α (x axis)
—
cos β (y axis)
—
cos γ (z axis)
—

Diagram: orange is ax, green is ay, blue is the resultant and the arc marks the direction angle from the +x axis. In 3D the diagram adds the z axis: purple is az, the dotted blue line is the xy-plane projection of the resultant, and x points toward you, y to the right and z up.

Average acceleration magnitude
—
In g
—
Average ax
—
Average ay
—
Average az
—
Direction in xy (0 to 360)
—
Velocity change |Δv|
—
Initial speed |v1|
—
Final speed |v2|
—
Speed change / time
—
Gap: |a| minus speed rate
—
Turn angle v1 to v2
—

Diagram: blue is v1, green is v2 and the dashed orange arrow is Δv = v2 − v1, drawn from the tip of v1 to the tip of v2 (xy-plane view, or a 3D view with x, y and z axes when either velocity has a z component). The average acceleration points the same way as Δv.

🧭 What is the Magnitude of Acceleration?

The magnitude of acceleration is the size of the acceleration vector: how quickly the velocity vector is changing, without regard to the direction of that change. Acceleration is a vector, so in two dimensions it has components ax and ay, and in three dimensions it also has az. Its magnitude is the length of the arrow they form, found with the Pythagorean theorem: |a| = sqrt(ax² + ay² + az²). It is measured in metres per second squared (m/s²), and is always zero or positive.

This quantity shows up whenever motion is not along a single line. A car taking a bend feels a forward or backward tangential acceleration from the throttle and brakes, plus a sideways centripetal acceleration from the turn. A thrown ball has a purely vertical acceleration of about 9.8 m/s² downward. A roller coaster rider has forward, vertical and sideways parts at once, and the total is often quoted in g. Engineers use the magnitude to compare loads, and students use it to check the answers to vector kinematics problems.

The most common misconception is that the magnitude of the acceleration equals the rate of change of speed. It does not. Speed is the magnitude of velocity, but acceleration is the rate of change of the whole velocity vector, so it also captures changes in direction. A satellite or a car on a roundabout moving at constant speed still accelerates, because its velocity vector keeps turning. The magnitude of the average acceleration is always at least as large as the change of speed divided by time, and the two agree only when the direction stays fixed.

This calculator handles both ways you usually meet the problem. In the components mode you enter ax, ay and optionally az, and get the magnitude, the direction angle in the xy-plane, the elevation angle, the direction cosines, and the result in g and ft/s². In the velocity-change mode you enter the initial and final velocity vectors and a time interval, and get the average acceleration vector and its magnitude, together with a direct comparison against the change of speed over time. Each mode draws a vector diagram. For one-dimensional problems with a single signed value, use the acceleration calculator instead.

📐 Formula

|a|  =  √(ax² + ay² + az²)
|a| = magnitude of acceleration (m/s²)
ax, ay, az = components along the x, y and z axes (m/s²); use az = 0 in 2D
Example: ax = 3, ay = 4.5 gives |a| = √(9 + 20.25) = 5.408 m/s²

Direction in the xy-plane, elevation and direction cosines:

θ  =  atan2(ay, ax),   φ  =  atan2(az, √(ax² + ay²)),   cos α = ax/|a|
θ = angle from the +x axis in the xy-plane, counterclockwise; add 360° to a negative value for the 0 to 360 form
φ = elevation above the xy-plane
cos α, cos β, cos γ = ax/|a|, ay/|a|, az/|a|, whose squares sum to 1

Average acceleration from a velocity change, with unit conversions:

aavg  =  (v2 − v1) ÷ Δt
v1, v2 = initial and final velocity vectors (m/s), subtracted component by component
Δt = time interval (s)
In g = |a| ÷ 9.80665    In ft/s² = |a| ÷ 0.3048
Note: |aavg| ≥ | |v2| − |v1| | ÷ Δt, with equality only when v1 and v2 point the same way

📖 How to Use This Calculator

Steps

1
Choose a mode: pick From components if you know ax, ay and az, or From velocity change if you know the initial and final velocity vectors and the time interval.
2
Enter the vector values: type the components in m/s² (or velocities in m/s and the time in seconds). Choose 2D to ignore the z component or 3D to include it.
3
Read the magnitude and direction: the result panel shows the magnitude in m/s², g and ft/s², the direction angles and cosines, or the average acceleration vector with a comparison to the change of speed over time.
4
Check the diagram: the arrows show the components and the angle, or v1, v2 and Δv, so you can confirm the signs and directions look right.

💡 Example Calculations

Example 1 — Car accelerating while turning

A car heading east at 15 m/s speeds up at 3 m/s² while turning left on a 50 m radius bend. What is the total acceleration?

1
Tangential component along the motion (east): ax = 3 m/s². Centripetal component toward the centre of the turn (north): ay = v²/r = 15²/50 = 4.5 m/s².
2
Magnitude: |a| = √(3² + 4.5²) = √29.25 = 5.408 m/s², which is 0.5515 g or 17.744 ft/s².
3
Direction: atan2(4.5, 3) = 56.31° from east toward north. Direction cosines are 0.5547 and 0.8321.
|a| = 5.408 m/s² (0.5515 g) at 56.31°
Try this example →

Example 2 — Ball in flight

A ball is in flight with no air resistance. Its acceleration is gravity only, ax = 0 and ay = -9.80665 m/s². What are the magnitude and direction?

1
Magnitude: |a| = √(0² + 9.80665²) = 9.80665 m/s², which is exactly 1 g or 32.174 ft/s².
2
Direction: atan2(-9.80665, 0) = -90°, which is 270° on the 0 to 360 scale. The vector points straight down.
|a| = 9.80665 m/s² (1 g) at 270° (-90° signed)
Try this example →

Example 3 — Roller coaster in g

A coaster car has acceleration components of 8 m/s² forward, 29.4 m/s² upward and 5 m/s² sideways. How many g is that?

1
Use 3D with ax = 8, ay = 29.4, az = 5. Magnitude: |a| = √(64 + 864.36 + 25) = 30.877 m/s².
2
In g: 30.877 / 9.80665 = 3.1485 g. In ft/s²: 30.877 / 0.3048 = 101.301.
3
The xy-plane part is 30.469 m/s² at 74.78°, and the elevation above that plane is 9.32°. Direction cosines: 0.2591, 0.9522, 0.1619.
|a| = 30.877 m/s² (3.1485 g), elevation 9.32°
Try this example →

Example 4 — East to north at constant speed

A vehicle moving east at 10 m/s turns to move north at 10 m/s over 5 s. What is the magnitude of its average acceleration?

1
v1 = (10, 0) and v2 = (0, 10). Velocity change: Δv = (-10, 10), so |Δv| = 14.142 m/s.
2
Average acceleration: (-10, 10) / 5 = (-2, 2) m/s², magnitude 2.828 m/s² at 135° (northwest).
3
Speed check: both speeds are 10 m/s, so change of speed over time is 0. The gap is 2.828 m/s², entirely due to the 90° turn.
|aavg| = 2.828 m/s² (0.2884 g), while speed change / time = 0
Try this example →

Example 5 — Straight-line speed-up

A car on a straight road goes from 10 m/s to 30 m/s east in 4 s. Do the two methods agree?

1
v1 = (10, 0), v2 = (30, 0), so Δv = (20, 0) and aavg = (5, 0) m/s². Magnitude 5 m/s² (0.5099 g).
2
Speed change over time: (30 - 10) / 4 = 5 m/s². The gap is 0 and the turn angle is 0°, because the direction never changed.
|aavg| = 5 m/s², equal to the speed rate, gap 0
Try this example →

❓ Frequently Asked Questions

How do you find the magnitude of acceleration from components?+
Square each component, add them, and take the square root: |a| = sqrt(ax² + ay² + az²). In 2D drop the az term. For ax = 3 and ay = 4.5 m/s² the magnitude is sqrt(9 + 20.25) = 5.408 m/s².
What is the difference between acceleration and the magnitude of acceleration?+
Acceleration is a vector with a size and a direction. Its magnitude is the size alone, always zero or positive, and measured in m/s². The magnitude does not tell you which way the velocity is being pushed.
Is the magnitude of average acceleration the change of speed divided by time?+
No. Average acceleration is the vector change in velocity divided by time. Its magnitude equals the speed change over time only if the direction does not change. Going from 10 m/s east to 10 m/s north in 5 s changes the speed by 0 but gives a magnitude of 2.828 m/s².
Can an object moving at constant speed have acceleration?+
Yes. Acceleration measures the change of the velocity vector, and velocity changes when direction changes. In uniform circular motion the speed is constant but the acceleration is v²/r, directed toward the centre.
How do I find the direction of the acceleration vector?+
In the xy-plane the angle from the +x axis is atan2(ay, ax). A negative result means below the x axis; add 360 to express it from 0 to 360 degrees. In 3D the elevation above the xy-plane is atan2(az, sqrt(ax² + ay²)).
What are direction cosines?+
They are the cosines of the angles between the vector and the x, y and z axes, equal to ax/|a|, ay/|a| and az/|a|. Their squares always add up to 1, which makes them a quick check on a 3D direction.
How do I convert m/s² to g?+
Divide by standard gravity, 9.80665 m/s². A magnitude of 30.877 m/s² is 3.1485 g. To get ft/s², divide m/s² by 0.3048, since one foot is exactly 0.3048 m; 1 g is about 32.174 ft/s².
How do I get acceleration from a change in velocity in two dimensions?+
Subtract the initial velocity vector from the final one component by component, then divide each component by the time interval. The magnitude of the resulting vector is the magnitude of the average acceleration.
Why is the average acceleration over a quarter circle smaller than v²/r?+
The instantaneous centripetal acceleration is v²/r throughout. The average over a quarter turn uses the straight-line velocity change, with magnitude v times root 2, divided by the time, which works out to about 0.9003 times v²/r. Over a full circle the average is zero.
Can the magnitude of acceleration be zero while an object moves?+
Yes. If velocity is constant in both size and direction, every component of acceleration is zero and so is the magnitude. A car cruising in a straight line at constant speed is an example.
What does a roller coaster acceleration in g mean?+
It is the magnitude of the acceleration divided by 9.80665 m/s². A kinematic magnitude of about 30.9 m/s² corresponds to about 3.15 g. Riders feel the vector sum of this and gravity, so the felt value is not identical to the kinematic one.

How do you find the magnitude of acceleration from components?

Square each component, add them, and take the square root: |a| = sqrt(ax^2 + ay^2 + az^2). In 2D drop the az term. For ax = 3 and ay = 4.5 m/s2 the magnitude is sqrt(9 + 20.25) = 5.408 m/s2.

What is the difference between acceleration and the magnitude of acceleration?

Acceleration is a vector with a size and a direction. Its magnitude is the size alone, always zero or positive, and measured in m/s2. The magnitude does not tell you which way the velocity is being pushed.

Is the magnitude of average acceleration the change of speed divided by time?

No. Average acceleration is the vector change in velocity divided by time. Its magnitude equals the speed change over time only if the direction does not change. Going from 10 m/s east to 10 m/s north in 5 s changes the speed by 0 but gives a magnitude of 2.828 m/s2.

Can an object moving at constant speed have acceleration?

Yes. Acceleration measures the change of the velocity vector, and velocity changes when direction changes. In uniform circular motion the speed is constant but the acceleration is v squared over r, directed toward the centre.

How do I find the direction of the acceleration vector?

In the xy-plane the angle from the +x axis is atan2(ay, ax). A negative result means below the x axis; add 360 to express it from 0 to 360 degrees. In 3D the elevation above the xy-plane is atan2(az, sqrt(ax^2 + ay^2)).

What are direction cosines?

They are the cosines of the angles between the vector and the x, y and z axes, equal to ax/|a|, ay/|a| and az/|a|. Their squares always add up to 1, which makes them a quick check on a 3D direction.

How do I convert m/s2 to g?

Divide by standard gravity, 9.80665 m/s2. A magnitude of 30.877 m/s2 is 3.1485 g. To get ft/s2, divide m/s2 by 0.3048, since one foot is exactly 0.3048 m; 1 g is about 32.174 ft/s2.

How do I get acceleration from a change in velocity in two dimensions?

Subtract the initial velocity vector from the final one component by component, then divide each component by the time interval. The magnitude of the resulting vector is the magnitude of the average acceleration.

Why is the average acceleration over a quarter circle smaller than v squared over r?

The instantaneous centripetal acceleration is v squared over r throughout. The average over a quarter turn is the chord-like change in velocity, which has magnitude v times root 2 over the time, about 0.9003 times v squared over r. Over a full circle the average is zero.

Can the magnitude of acceleration be zero while an object moves?

Yes. If velocity is constant in both size and direction, every component of acceleration is zero and so is the magnitude. A car cruising in a straight line at constant speed is an example.

What does a roller coaster acceleration in g mean?

It is the magnitude of the acceleration divided by 9.80665 m/s2. A kinematic magnitude of about 30.9 m/s2 corresponds to about 3.15 g. Riders feel the vector sum of this and gravity, so the felt value is not identical to the kinematic one.