Impact Energy Calculator

Find the energy delivered when a dropped or moving object hits something, the matching fall height, and the average force from the stopping distance.

🔨 Impact Energy Calculator
Mass (m)
kg
0.1 kg500 kg
Drop height (h)
m
0.1 m100 m
Gravity (g)
Earth 9.80665, Moon 1.62, Mars 3.721 m/s²
Mass (m)
kg
0.01 kg3000 kg
Speed (v)
0200 (in the chosen unit)
Gravity for the fall height (g)
m/s²
Mass (m)
kg
0.01 kg3000 kg
Energy comes from
Impact speed (v)
0100 (in the chosen unit)
Drop height (h, Earth gravity)
m
0.1 m100 m
Stop is described by
Stopping distance (d)
Stopping time (t)
Impact energy (E = m g h)
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Impact speed (m/s)
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Impact speed (km/h)
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Impact speed (mph)
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Momentum at impact
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Fall time
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Same as lifting 1 kg by
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Same as 1 kg moving at
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Energy in kilowatt hours
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Charts: energy rises in a straight line with height (E = m g h) while speed follows a square-root curve (v = √(2 g h)). The blue dot and dashed line mark your drop height. Two charts are used because the two curves have different shapes and units.

Kinetic energy (½ m v²)
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Equivalent drop height
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Speed (m/s)
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Speed (km/h)
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Speed (mph)
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Momentum
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Energy in kilojoules
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Free-fall time to reach this speed
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Chart: kinetic energy is a parabola in speed, so each doubling of speed quadruples the energy. The equivalent drop height has exactly the same shape (it is the energy divided by m g), so it is given in the results instead of a second chart. The blue dot and dashed line mark your speed.

Average stopping force (F = E / d)
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Average force (kN)
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Energy to remove
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Deceleration in g (F / m g)
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Deceleration (m/s²)
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Impact speed
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Stopping distance
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Stopping time (steady stop)
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Force on the ground for a vertical stop (adds m g)
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Chart: both axes are logarithmic, so the hyperbola F = E / d appears as a straight line sloping down. Each step to the right of one decade lowers the average force by a factor of ten. The blue dot and dashed line mark your stopping distance. The average is smoothed over the stop, so the peak is higher.

🔨 What is the Impact Energy Calculator?

Impact energy is the energy an object carries into a collision, and therefore the energy that the thing it hits, or the object itself, has to absorb. For a falling object it comes from the gravitational potential energy lost during the drop, E = m g h. For a moving object it is the kinetic energy, E = ½ m v². The two are the same number when an object falls freely and nothing else takes energy away, which is why this calculator treats a drop height and a speed as two ways of describing one quantity, measured in joules.

The calculator has three modes. Drop from height takes a mass, a height and a gravity value (Earth, the Moon, Mars or your own) and returns the impact energy, the impact speed in three units, the momentum and the fall time. Moving object takes a mass and a speed in m/s, km/h or mph and returns the kinetic energy and the equivalent drop height h = v² / (2g), the height from which a free fall would reach that speed. Impact force adds the missing ingredient for forces, the distance or time over which the object stops, and returns the average force and the deceleration in multiples of g.

Typical uses include a quick check of how hard a dropped tool, tile or box will land, translating the speed of a vehicle or a ball into an intuitive fall height, comparing how a crumple zone or a bent knee spreads a stop over a longer distance, and teaching the work-energy theorem. The equivalents in the results (lifting 1 kg by a given height, a 1 kg mass moving at a given speed, kilowatt hours) are computed directly from the energy, so they are exact conversions, not statistics.

Two points are often misunderstood. Energy and force are different things: the same energy can be delivered as a modest force over a long stop or as an enormous force over a short one, so the energy alone does not say how damaging an impact is. And the force in the third mode is an average. Real impact forces peak above the average, part of the energy turns into heat and sound, and the stopping time depends on how the materials deform. For the peak and the time dependence, use the impulse and momentum calculator. For the energy of a moving object alone see the kinetic energy calculator, and for long falls where drag matters see the terminal velocity calculator.

📐 Impact Energy Formulas

Drop:   E = m g h  =  ½ m v²  ,   v = √(2 g h)  ,   t = √(2 h / g)  ,   p = m v
Moving:   E = ½ m v²  and  heq = v² / (2 g)
Force:   Favg = E / d  =  m v / t  ,   d = v t / 2  ,   deceleration in g = Favg / (m g)
E = impact energy, in joules (J)
m = mass, in kilograms
g = gravitational acceleration, 9.80665 m/s² on Earth (standard gravity), 1.62 on the Moon, 3.721 on Mars
h = drop height, in metres; heq = equivalent drop height
v = speed at impact, in m/s (1 km/h = 0.27778 m/s, 1 mph = 0.44704 m/s)
t = fall time or stopping time, in seconds; p = momentum, in kg·m/s
d = stopping distance, in metres, and Favg = average net stopping force, in newtons
Example: m = 2 kg, h = 3 m on Earth gives E = 58.84 J and v = 7.671 m/s

For a drop, energy conservation says the potential energy m g h is converted into kinetic energy ½ m v², which gives v = √(2 g h) and shows that the mass cancels out of the speed. For the stop, the work-energy theorem states that the net work done on an object equals its change in kinetic energy. A constant average force F acting over a stopping distance d does work F d, and stopping the object removes all of its kinetic energy E, so F d = E. If the deceleration is steady, the average speed during the stop is v/2, so d = v t / 2, and the same force follows from the impulse form F = m v / t. The equivalent drop height is just the energy divided by m g, which is why it depends on speed and gravity but not on mass. In a vertical landing the surface also has to hold up the weight, so the force it exerts is F + m g.

📖 How to Use This Calculator

Steps

1
Choose a mode - Drop from height for a falling object, Moving object when you know a speed, or Impact force to find an average force from a stopping distance or time.
2
Enter the mass - type it in kilograms. For a drop, add the height and pick Earth, Moon, Mars or a custom gravity. The planet menu only fills the gravity box.
3
Enter the speed or the stop - in Moving object and Impact force, set the speed and its unit. In Impact force, describe the stop by a distance (such as a crumple length) or a time.
4
Read the results and the chart - results update as you type. The chart marks your current value with a dot, and the note below the results explains what the numbers assume.

💡 Example Calculations

Example 1 — A tool dropped from 3 m

2 kg tool dropped from 3 m on Earth (g = 9.80665 m/s², no air resistance)

1
Energy: E = m g h = 2 × 9.80665 × 3 = 58.84 J
2
Speed: v = √(2 × 9.80665 × 3) = √58.84 = 7.671 m/s, which is 27.61 km/h or 17.16 mph. Fall time = √(2 × 3 / 9.80665) = 0.7822 s.
3
Momentum p = 2 × 7.671 = 15.34 kg·m/s. The same energy would lift a 1 kg mass by 6 m, or equals a 1 kg mass moving at 10.85 m/s.
Impact energy = 58.84 J at 7.671 m/s
Try this example →

Example 2 — Car hitting a barrier with a crumple zone

1,500 kg car at 50 km/h stopped by 0.5 m of crumple (illustrative values)

1
Speed: 50 km/h = 13.889 m/s. Energy: E = ½ × 1500 × 13.889² = 144,675.9 J.
2
Average force: F = E / d = 144,675.9 / 0.5 = 289,351.9 N, a deceleration of 192.9 m/s² or 19.67 g.
3
Steady stop time = 2 d / v = 2 × 0.5 / 13.889 = 72 ms. Halving the crumple to 0.25 m would double the average force to about 578,704 N. The peak is higher than the average.
Average force = 289,352 N (19.67 g)
Try this example →

Example 3 — Jumping from 1 m with bent knees

70 kg person lands after a 1 m drop and stops over 0.5 m of knee flexion (illustrative, not a safety limit)

1
Landing speed: v = √(2 × 9.80665 × 1) = 4.429 m/s. Energy: E = 70 × 9.80665 × 1 = 686.47 J.
2
Average net stopping force: F = 686.47 / 0.5 = 1,372.9 N, which is exactly 2.00 g because the stopping distance is twice the drop height.
3
Steady stop time = 2 × 0.5 / 4.429 = 225.8 ms. Adding the person's weight (686.5 N) gives about 2,059.4 N from the ground. A stiff landing over a few centimetres would give a much larger force for the same energy.
Average stopping force = 1,372.9 N (2.00 g)
Try this example →

Example 4 — A baseball at 40 m/s

0.145 kg baseball travelling at 40 m/s (illustrative values)

1
Energy: E = ½ × 0.145 × 40² = 116 J. Momentum = 0.145 × 40 = 5.8 kg·m/s.
2
Equivalent drop height: h = 40² / (2 × 9.80665) = 81.58 m. The speed is 144 km/h or 89.48 mph.
3
Free-fall time to reach 40 m/s is 40 / 9.80665 = 4.079 s, without air resistance.
Kinetic energy = 116 J, like a fall of 81.58 m
Try this example →

Example 5 — A car at 50 km/h as a fall height

1,500 kg car at 50 km/h, expressed as a drop height

1
Speed: 50 km/h = 13.889 m/s.
2
Equivalent drop height: h = 13.889² / (2 × 9.80665) = 9.835 m. Energy: E = ½ × 1500 × 13.889² = 144,675.9 J (144.68 kJ).
3
Doubling the speed to 100 km/h gives four times the energy (578,703.7 J) and an equivalent height of 39.34 m.
Energy = 144,675.9 J, like a fall of 9.835 m
Try this example →

❓ Frequently Asked Questions

How do you calculate impact energy from a drop height?+
Multiply mass, gravity and height: E = m g h. A 2 kg tool dropped from 3 m on Earth arrives with E = 2 × 9.80665 × 3 = 58.84 J. This equals the kinetic energy at impact, ½ m v², if air resistance is ignored. The calculator also gives the impact speed, momentum and fall time.
How do you find impact speed from drop height?+
Use v = √(2 g h). From 3 m on Earth, v = 7.67 m/s, about 27.6 km/h. The mass does not appear in the formula, so a heavy and a light object dropped together reach the same speed in a vacuum. Air resistance lowers the real speed for light or bulky objects.
What is the equivalent drop height of a speed?+
It is h = v² / (2 g), the height from which a free fall would reach that speed. At 50 km/h (13.889 m/s) on Earth it is 9.84 m. It expresses a speed as a fall height, and it depends only on speed and gravity. The energy at that height still depends on the mass.
How do you calculate average impact force?+
Use the work-energy theorem: force times stopping distance equals the energy removed, so Favg = E / d. A 1,500 kg car at 50 km/h has 144,676 J. Stopping in 0.5 m of crumple needs an average force of about 289,352 N. It is an average over the stopping distance, not the peak.
Why does a longer stopping distance reduce the impact force?+
The energy to remove is fixed by mass and speed, and work equals force times distance, so F = E / d. Doubling d halves F. That is the principle behind crumple zones, padded surfaces, airbags and bending your knees on landing. The log-log chart on this page shows the same relationship as a straight line.
Does mass or height matter more for impact energy?+
Both enter linearly in E = m g h, so doubling either one doubles the energy. Speed behaves differently: it depends only on height and grows with its square root. Doubling the height gives 1.41 times the speed but 2 times the energy, and doubling the speed of a moving object gives 4 times the energy.
How is impact energy different from impact force?+
Energy, in joules, is the total amount to be absorbed. Force, in newtons, is how hard the object pushes during the stop. The same energy can produce a small force over a long stopping distance or a huge one over a short distance. Force needs the stopping distance or time as an extra input, as the third mode does.
Does the calculator include air resistance?+
No. Drop mode assumes free fall with constant gravity, which is accurate for short drops of dense objects and overestimates the speed for long falls or light, bulky objects. When drag matters, the speed approaches a terminal velocity lower than √(2 g h). Use the terminal velocity calculator for that case.
What gravity values does the planet menu use?+
Earth uses the standard gravity 9.80665 m/s², the Moon 1.62 m/s² and Mars 3.721 m/s². The menu only fills the gravity box, so you can still type any value. On the Moon the 2 kg tool dropped from 3 m has energy 9.72 J and arrives at 3.12 m/s, against 58.84 J and 7.67 m/s on Earth.
How many joules is a 1 kg object dropped from 1 m?+
On Earth, E = 1 × 9.80665 × 1 = 9.80665 J, roughly 9.8 J, and the impact speed is 4.43 m/s. Equivalently, 9.80665 J is the energy needed to lift 1 kg by 1 m, which is why the calculator reports the height by which this energy could lift a 1 kg mass.
Why is the real peak force higher than the average force?+
The average spreads the stop evenly over the distance, but real forces rise, peak and fall, and part of the energy goes to heat, sound and permanent deformation. The peak therefore exceeds the average. The impulse and momentum calculator shows peak factors for simple pulse shapes. Do not treat the average as a pass or fail limit.
What is the link between impact energy and the work-energy theorem?+
The theorem says the net work on an object equals its change in kinetic energy. For a stop, the final kinetic energy is zero, so the work done by the stopping force equals the impact energy. See the work, energy and power calculator for more worked cases of work, energy and power.

How do you calculate impact energy from a drop height?

Multiply mass, gravity and height: E = m g h. A 2 kg tool dropped from 3 m on Earth arrives with E = 2 x 9.80665 x 3 = 58.84 J. This equals the kinetic energy at impact, E = 1/2 m v^2, if air resistance is ignored. The calculator also gives the impact speed, momentum and fall time.

How do you find impact speed from drop height?

Use v = sqrt(2 g h). From 3 m on Earth, v = sqrt(2 x 9.80665 x 3) = 7.67 m/s, about 27.6 km/h. The mass does not appear in the formula, so a heavy and a light object dropped together reach the same speed in a vacuum. Air resistance lowers the real speed for light or bulky objects.

What is the equivalent drop height of a speed?

It is h = v^2 / (2 g), the height from which a free fall would reach that speed. At 50 km/h (13.889 m/s) on Earth it is 9.84 m. The comparison is useful because it expresses a car speed as a fall height, but it only matches energy per kilogram, so the same height means very different energy for different masses.

How do you calculate average impact force?

Use the work-energy theorem: the force times the stopping distance equals the energy removed, so F_avg = E / d. A 1,500 kg car at 50 km/h has 144,676 J. Stopping in 0.5 m of crumple needs an average force of about 289,352 N. The number is an average over the stopping distance, not the peak.

Why does a longer stopping distance reduce the impact force?

The energy to be removed is fixed by mass and speed, and work equals force times distance, so F = E / d. Doubling d halves F. That is the principle behind crumple zones, padded surfaces, airbags and bending your knees on landing. The force per unit of stopping distance is what the chart on the page shows.

Does the mass or the height matter more for impact energy?

Both enter linearly in E = m g h, so doubling either one doubles the energy. Speed behaves differently: it depends only on height, and grows with the square root of height. Doubling the height gives 1.41 times the speed but 2 times the energy, and doubling the speed of a moving object gives 4 times the energy.

How is impact energy different from impact force?

Energy, in joules, is the total amount that has to be absorbed. Force, in newtons, is how hard the object pushes during the stop. The same energy can produce a small force over a long stopping distance or a huge force over a short one. Force needs the stopping distance or time as an extra input, as the third mode of this calculator does.

Does the calculator include air resistance?

No. Drop mode assumes free fall with constant gravity, which is accurate for short drops of dense objects and overestimates speed for long falls or light, bulky objects. Once drag matters, the speed approaches a terminal velocity that is lower than sqrt(2 g h). Use the terminal velocity calculator for that case.

What gravity values does the planet menu use?

Earth uses the standard gravity 9.80665 m/s squared, the Moon 1.62 m/s squared and Mars 3.721 m/s squared. The menu only fills the gravity box, so you can still type any other value. On the Moon the same 2 kg tool dropped from 3 m has energy 9.72 J and arrives at 3.12 m/s.

How many joules is a drop of 1 kg from 1 m?

On Earth, E = 1 x 9.80665 x 1 = 9.80665 J, so roughly 9.8 J. The impact speed is 4.43 m/s. In the other direction, 9.80665 J is also the energy needed to lift a 1 kg mass by 1 m, which is why the calculator reports the height you could lift 1 kg with the impact energy.

Why is the real force higher than the average force?

The average spreads the stop evenly over the distance, but real forces rise, peak and fall, and part of the energy goes to heat, sound and permanent deformation. The peak therefore exceeds the average. The impulse and momentum calculator shows peak factors for simple pulse shapes. Never use the average as a pass or fail limit.