Centripetal Force Calculator

Find the inward force that keeps a mass moving in a circle, from speed, rpm or period, with banked-curve and loop cases.

🎡 Centripetal Force Calculator
Mass (m)
Radius of the circle (r)
Speed (v)
Rotation rate
Period (T)time for one full turn
Design speedfrictionless curve
Speed at the top of the loopbottom speed follows from energy conservation
Centripetal force
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Force (lbf)
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Centripetal acceleration
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Acceleration in g
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Angular velocity
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Rotation rate
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Period
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Speed (m/s)
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Speed (km/h)
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Ideal bank angle
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Centripetal force
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Normal force
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Weight m g
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Lateral acceleration
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Road slope (tan θ)
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Design speed
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Bank angle (radians)
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Normal force at the top
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Normal force at the bottom
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Completes the loop?
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Minimum speed at the top
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Minimum speed at the bottom
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Speed at the bottom
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Apparent weight at the top
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Apparent weight at the bottom
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🎡 What is Centripetal Force?

Centripetal force is the net inward force that makes an object follow a circular path. The word means "center-seeking". Any object moving in a circle at speed v on a radius r is accelerating toward the center at a = v² / r, even if its speed never changes, because the direction of its velocity is always turning. Newton's second law then says the inward force must be F = m v² / r. The same force can be written F = m w² r with the angular velocity w, or F = 4 pi² m r / T² with the period T of one turn. This calculator accepts any of these descriptions and also covers two classic special cases, the frictionless banked curve and the vertical loop.

The key idea is that centripetal force is not a new kind of force. It is a requirement that some real force must meet. For a ball on a string it is the tension, for a car on a flat road it is friction, for a satellite it is gravity, and for an electron in a magnetic field it is the magnetic force. When you draw a free-body diagram you should draw those real forces and then notice that their inward sum equals m v² / r. If the available force falls short, for example on an icy road, the object cannot follow the circle and moves off along a straight tangent. The opposite viewpoint, the outward push felt by someone riding in the rotating frame, is the fictitious force handled by the centrifugal force calculator.

Engineers use these formulas to design highway curves, roller coasters, centrifuges and flywheels. A banked road tilts the normal force so that part of it points toward the center of the curve, and at the right design speed no friction is needed at all. A vertical loop is harder to analyse because gravity helps at the top and opposes at the bottom, so the normal force changes around the circle. Both cases are solved here with the same inertial-frame reasoning. Once you have the force, the force calculator and the net force calculator help you combine it with other forces, and the normal force calculator covers the straight-line cases.

A few common mistakes are worth avoiding. Centripetal force does no work, because it is perpendicular to the velocity, so it never changes the speed. The force grows with the square of the speed, so a small increase in speed demands a large increase in grip. And the radius must be the radius of the path itself, not a diameter or the distance to some other point.

📐 Formula

Fc  =  m v² / r  =  m ω² r  =  4π² m r / T²
Fc = net inward force in newtons (N), pointing at the center of the circle.
m = mass in kilograms. Grams and pounds are converted (1 lb = 0.45359237 kg).
v = speed along the circle in m/s, and ω = v / r = 2π / T is the angular velocity in rad/s.
r = radius of the circular path in metres, T = period of one full turn in seconds.
Banked curve (no friction): tan θ = v² / (r g), normal force N = m g / cos θ, with g = 9.80665 m/s².
Vertical loop: Ntop = m v² / r − m g, and Nbottom = m v² / r + 5 m g where v is the speed at the top. The bottom speed is vb² = v² + 4 g r from energy conservation.
Minimum loop speeds: √(g r) at the top and √(5 g r) at the bottom.
Example: m = 1200 kg, r = 50 m, v = 20 m/s gives F = 1200 × 400 / 50 = 9,600 N.

📖 How to Use This Calculator

Steps

1
Pick the situation. Choose From speed, From rotation rate or From period for general circular motion. Choose Banked curve or Vertical loop for those special cases.
2
Enter mass and radius. Type the mass and the radius of the path and choose the units. Set the unit first, because a dropdown only changes how your typed number is read.
3
Enter the motion. Type the speed, rotation rate, period or design speed that goes with your mode, and choose its unit.
4
Read the results and chart. The inward force, acceleration in g, bank angle or normal forces appear below, with a chart that marks your input on the curve.

💡 Example Calculations

Example 1 — A Car on a Flat Curve

A 1200 kg car takes a 50 m radius curve at 72 km/h

1
Convert the speed: 72 / 3.6 = 20.000 m/s.
2
a = v² / r = 400 / 50 = 8.0000 m/s², which is 0.8158 g.
3
F = m a = 1200 × 8 = 9,600.0 N, supplied entirely by tyre friction.
Force = 9,600.0 N, acceleration = 0.8158 g
Try this example →

Example 2 — A Ball on a String

A 0.5 kg ball swung in a horizontal circle on a 1.2 m string at 2 revolutions per second

1
ω = 2 × 2π = 12.566 rad/s, so the speed is 12.566 × 1.2 = 15.080 m/s.
2
a = ω² r = 157.91 × 1.2 = 189.50 m/s².
3
F = 0.5 × 189.50 = 94.748 N, which is the tension in the string.
Force = 94.748 N, period = 0.5000 s
Try this example →

Example 3 — A Space Station in Orbit

A 420,000 kg station on a 6,780 km orbital radius with a period of 92.68 minutes

1
T = 92.68 × 60 = 5,560.8 s and r = 6,780,000 m.
2
a = 4π² r / T² = 8.6560 m/s², which is 0.8827 g.
3
F = 420,000 × 8.6560 = 3,635,500.2 N, supplied by gravity. The orbital speed is 7,660.8 m/s.
Force = 3,635,500.2 N, speed = 7,660.8 m/s
Try this example →

Example 4 — A Banked Highway Curve

A 1200 kg car at 90 km/h on a frictionless curve of radius 120 m

1
v = 90 / 3.6 = 25 m/s, so tan θ = 625 / (120 × 9.80665) = 0.5311.
2
θ = arctan(0.5311) = 27.973°.
3
F = m v² / r = 1200 × 625 / 120 = 6,250.0 N and N = m g / cos θ = 11,768.0 / 0.8832 = 13,324.7 N.
Bank angle = 27.973°, normal force = 13,324.7 N
Try this example →

Example 5 — A Roller Coaster Loop

A 70 kg rider on a loop of radius 10 m, passing the top at 12 m/s

1
m v² / r = 70 × 144 / 10 = 1,008.0 N, and the weight is 70 × 9.80665 = 686.47 N.
2
Ntop = 1,008.0 − 686.47 = 321.53 N. The minimum top speed is √(9.80665 × 10) = 9.9029 m/s, so the rider stays on the track.
3
Nbottom = 1,008.0 + 5 × 686.47 = 4,440.3 N, an apparent weight of 6.4684 g. The bottom speed is 23.157 m/s.
Top = 321.53 N, bottom = 4,440.3 N, completes the loop
Try this example →

❓ Frequently Asked Questions

What is the formula for centripetal force?+
Centripetal force is F = m v² / r, where m is the mass, v the speed along the circle and r the radius. It can also be written m w² r or 4 pi² m r / T². A 1200 kg car at 20 m/s on a 50 m radius needs 9600 N.
How do you calculate centripetal force from rpm?+
Convert rpm to rad/s with w = rpm x 2 pi / 60, then use F = m w² r. A 0.5 kg ball on a 1.2 m string turning at 2 revolutions per second gives w = 12.566 rad/s and F = 94.75 N.
What provides the centripetal force on a car in a turn?+
Friction between the tyres and the road, plus any horizontal component of the normal force on a banked road. If the needed force exceeds what friction can supply, the car slides outward.
What is the ideal banking angle for a curve?+
The angle satisfies tan(theta) = v² / (r g). At 25 m/s on a 120 m curve it is 27.97 degrees. At that speed no friction is needed, and the angle does not depend on the mass of the vehicle.
What is the difference between centripetal and centrifugal force?+
Centripetal force is the real inward force on an object moving in a circle. Centrifugal force is the apparent outward force felt in the rotating frame. They have the same size, m v² / r, but opposite directions.
What is the minimum speed to complete a vertical loop?+
At the top the speed must be at least sqrt(g r), because gravity alone then supplies the centripetal force. At the bottom that corresponds to sqrt(5 g r). For a 10 m radius loop that is 9.90 m/s at the top and 22.14 m/s at the bottom.
How does centripetal force change with radius?+
At a fixed speed the force is inversely proportional to the radius, so a tighter turn needs more force. At a fixed rotation rate the force is proportional to the radius instead.
Does centripetal force do work?+
No. The force is perpendicular to the velocity at every instant, so it changes the direction of the motion but not the speed or the kinetic energy of the object.
What is centripetal acceleration?+
It is the inward acceleration a = v² / r = w² r that points to the centre of the circle. Newton's second law then gives the force as F = m a. At 20 m/s on a 50 m radius it is 8 m/s², or 0.816 g.
Why do you feel pushed outward in a turn?+
Your body tends to continue in a straight line, while the car turns toward the centre. From inside the car this looks like an outward push, which is the fictitious centrifugal force of the rotating frame.
Why does the bottom of a loop feel so much heavier than the top?+
At the bottom the normal force must both support the weight and supply the centripetal force, and the rider is also moving faster. The difference between the two normal forces is always 6 m g, so the apparent weight at the bottom exceeds that at the top by exactly 6 g.

What is the formula for centripetal force?

Centripetal force is F = m v² / r, where m is the mass, v the speed along the circle and r the radius. It can also be written m w² r or 4 pi² m r / T². A 1200 kg car at 20 m/s on a 50 m radius needs 9600 N.

How do you calculate centripetal force from rpm?

Convert rpm to rad/s with w = rpm x 2 pi / 60, then use F = m w² r. A 0.5 kg ball on a 1.2 m string turning at 2 revolutions per second gives w = 12.566 rad/s and F = 94.75 N.

What provides the centripetal force on a car in a turn?

Friction between the tyres and the road, plus any horizontal component of the normal force on a banked road. If the needed force exceeds what friction can supply, the car slides outward.

What is the ideal banking angle for a curve?

The angle satisfies tan(theta) = v² / (r g). At 25 m/s on a 120 m curve it is 27.97 degrees. At that speed no friction is needed, and the angle does not depend on the mass of the vehicle.

What is the difference between centripetal and centrifugal force?

Centripetal force is the real inward force on an object moving in a circle. Centrifugal force is the apparent outward force felt in the rotating frame. They have the same size, m v² / r, but opposite directions.

What is the minimum speed to complete a vertical loop?

At the top the speed must be at least sqrt(g r), because gravity alone then supplies the centripetal force. At the bottom that corresponds to sqrt(5 g r). For a 10 m radius loop that is 9.90 m/s at the top and 22.14 m/s at the bottom.

How does centripetal force change with radius?

At a fixed speed the force is inversely proportional to the radius, so a tighter turn needs more force. At a fixed rotation rate the force is proportional to the radius instead.

Does centripetal force do work?

No. The force is perpendicular to the velocity at every instant, so it changes the direction of the motion but not the speed or the kinetic energy of the object.

What is centripetal acceleration?

It is the inward acceleration a = v² / r = w² r that points to the centre of the circle. Newton's second law then gives the force as F = m a. At 20 m/s on a 50 m radius it is 8 m/s², or 0.816 g.

Why do you feel pushed outward in a turn?

Your body tends to continue in a straight line, while the car turns toward the centre. From inside the car this looks like an outward push, which is the fictitious centrifugal force of the rotating frame.