Relativistic Momentum Calculator

Find relativistic momentum p = γmv, correcting classical momentum for particles moving near the speed of light.

🚀 Relativistic Momentum Calculator
m/s
kg
Relativistic momentum (p)
Lorentz factor (γ)
Classical momentum (mv)
Step-by-step working

🚀 What is the Relativistic Momentum Calculator?

This relativistic momentum calculator finds p=γmv, the correct momentum formula for particles moving at a significant fraction of the speed of light. Enter a velocity and choose an electron, proton, or custom rest mass, and it returns the relativistic momentum, the Lorentz factor, and the classical mv value for comparison.

p = γmv corrects classical momentum by the Lorentz factor γ, which stays near 1 at everyday speeds but grows without bound as velocity approaches the speed of light c.

Unlike classical momentum, relativistic momentum is the quantity that is actually conserved in particle collisions at any speed, which is why particle physicists always use this formula rather than the classical mv approximation.

This calculator is useful for particle physics and special relativity students, and for anyone working with high-energy accelerator or cosmic ray physics problems.

📐 Formula

p  =  γ m v
γ = 1/√(1−β²), β=v/c
m = rest mass, v = velocity
Reduces to classical p=mv when v « c
Example: electron at v=0.9c: p ≈ 5.6387×10⁻²² kg·m/s (γ≈2.294157, vs. 2.4578×10⁻²² classical).

📖 How to Use This Calculator

Steps

1
Enter the velocity.
2
Choose a particle preset or custom mass.
3
Read the relativistic momentum compared to classical.

💡 Example Calculations

Example 1 - Electron at 50% of c

1
v=1.4990×10⁸ m/s (50% of c), electron
2
γ = 1.154701
3
p = 1.5767 × 10⁻²² kg·m/s (classical: 1.3655×10⁻²²)
p = 1.5767 × 10⁻²² kg·m/s
Try this example →

Example 2 - Electron at 90% of c

1
v=2.6981×10⁸ m/s (90% of c), electron
2
γ = 2.294157
3
p = 5.6387 × 10⁻²² kg·m/s (more than double the classical value)
p = 5.6387 × 10⁻²² kg·m/s
Try this example →

Example 3 - Electron at 99% of c

1
v=2.9679×10⁸ m/s (99% of c), electron
2
γ = 7.088812
3
p = 1.9165 × 10⁻²¹ kg·m/s, over 7x the classical value
p = 1.9165 × 10⁻²¹ kg·m/s
Try this example →

❓ Frequently Asked Questions

What is relativistic momentum?+
Relativistic momentum is the correct, frame-invariant definition of momentum under Einstein's special relativity: p = γmv, where γ is the Lorentz factor. Unlike the classical formula p = mv, this version remains conserved in collisions and interactions even when particles move at a significant fraction of the speed of light.
What is the formula for relativistic momentum?+
p = γmv, where γ = 1/√(1−β²) is the Lorentz factor, m is the particle's rest mass, and v is its velocity. As v approaches the speed of light c, γ grows without bound, so momentum increases far faster than the classical mv formula would predict.
How is relativistic momentum different from classical momentum?+
Classical momentum p = mv assumes mass and velocity combine linearly with no upper speed limit. Relativistic momentum multiplies this by γ, which stays near 1 at low speeds (recovering the classical formula) but diverges as v → c, correctly reflecting that no massive particle can ever reach the speed of light no matter how much momentum it has.
Why does momentum increase without bound as speed approaches c?+
Because γ diverges to infinity as β → 1, the relativistic momentum formula shows that accelerating a massive particle ever closer to the speed of light requires ever-increasing momentum (and correspondingly energy), which is why reaching or exceeding c is physically impossible for any object with nonzero rest mass.
Is relativistic momentum conserved the same way classical momentum is?+
Yes, relativistic momentum p = γmv is the quantity that is actually conserved in particle collisions and interactions across all inertial reference frames, exactly the role classical momentum plays in Newtonian mechanics. This is why particle physicists always use the relativistic definition, not the classical one, when analyzing high-energy collisions.
When does relativistic momentum reduce to classical momentum?+
At low speeds (β well under about 0.1, or roughly 30,000 km/s), γ is extremely close to 1, so p ≈ mv to high precision. This is why classical mechanics works so well for everyday objects and low-speed engineering applications.
How is relativistic momentum related to relativistic energy?+
They are linked through the energy-momentum relation E² = (pc)² + (mc²)², which combines a particle's total relativistic energy, momentum, and rest mass energy into a single invariant equation valid in every reference frame.
What particles use extremely high relativistic momentum in practice?+
Particle accelerators like the LHC push protons to enormous relativistic momenta (γ in the thousands), and cosmic rays observed on Earth can carry relativistic momenta corresponding to macroscopic kinetic energies concentrated in a single subatomic particle, both regimes where the classical mv formula would be wildly wrong.
Does relativistic momentum depend on the direction of motion?+
No, like classical momentum, relativistic momentum is a vector whose magnitude is γmv and whose direction matches the particle's velocity direction; this calculator computes the magnitude for a given speed.
What units does this calculator use for momentum?+
Results are given in kilogram-metres per second (kg·m/s), the SI unit for momentum, alongside the classical (non-relativistic) mv value for direct comparison.

What is relativistic momentum?

Relativistic momentum is the correct, frame-invariant definition of momentum under Einstein's special relativity: p = γmv, where γ is the Lorentz factor. Unlike the classical formula p = mv, this version remains conserved in collisions and interactions even when particles move at a significant fraction of the speed of light.

What is the formula for relativistic momentum?

p = γmv, where γ = 1/√(1−β²) is the Lorentz factor, m is the particle's rest mass, and v is its velocity. As v approaches the speed of light c, γ grows without bound, so momentum increases far faster than the classical mv formula would predict.

How is relativistic momentum different from classical momentum?

Classical momentum p = mv assumes mass and velocity combine linearly with no upper speed limit. Relativistic momentum multiplies this by γ, which stays near 1 at low speeds (recovering the classical formula) but diverges as v → c, correctly reflecting that no massive particle can ever reach the speed of light no matter how much momentum it has.

Why does momentum increase without bound as speed approaches c?

Because γ diverges to infinity as β → 1, the relativistic momentum formula shows that accelerating a massive particle ever closer to the speed of light requires ever-increasing momentum (and correspondingly energy), which is why reaching or exceeding c is physically impossible for any object with nonzero rest mass.

Is relativistic momentum conserved the same way classical momentum is?

Yes, relativistic momentum p = γmv is the quantity that is actually conserved in particle collisions and interactions across all inertial reference frames, exactly the role classical momentum plays in Newtonian mechanics. This is why particle physicists always use the relativistic definition, not the classical one, when analyzing high-energy collisions.

When does relativistic momentum reduce to classical momentum?

At low speeds (β well under about 0.1, or roughly 30,000 km/s), γ is extremely close to 1, so p ≈ mv to high precision. This is why classical mechanics works so well for everyday objects and low-speed engineering applications.

How is relativistic momentum related to relativistic energy?

They are linked through the energy-momentum relation E² = (pc)² + (mc²)², which combines a particle's total relativistic energy, momentum, and rest mass energy into a single invariant equation valid in every reference frame.

What particles use extremely high relativistic momentum in practice?

Particle accelerators like the LHC push protons to enormous relativistic momenta (γ in the thousands), and cosmic rays observed on Earth can carry relativistic momenta corresponding to macroscopic kinetic energies concentrated in a single subatomic particle, both regimes where the classical mv formula would be wildly wrong.

Does relativistic momentum depend on the direction of motion?

No, like classical momentum, relativistic momentum is a vector whose magnitude is γmv and whose direction matches the particle's velocity direction; this calculator computes the magnitude for a given speed.

What units does this calculator use for momentum?

Results are given in kilogram-metres per second (kg·m/s), the SI unit for momentum, alongside the classical (non-relativistic) mv value for direct comparison.