Isotope Production and Burnup Calculator
Compute isotope production activity and saturation fraction from neutron flux, activation cross-section, and irradiation time, or find target burnup fraction and remaining atoms.
⚛️ What Is Isotope Production and Target Burnup?
Isotope production by neutron activation is the process of placing a stable target material in a neutron flux, causing target nuclei to absorb neutrons and transmute into radioactive product isotopes. The activity of the product builds up over time according to A(t) = N × σ × φ × (1 − exp(−λt)), where N is the number of target atoms, σ is the neutron activation cross-section in barns (1 barn = 10−24 cm2), φ is the neutron flux in n/cm2/s, and λ = ln(2)/T1/2 is the decay constant of the radioactive product. This formula accounts for both the continuous production of new product atoms by neutron capture and their simultaneous radioactive decay.
The quantity N × σ × φ is the saturation activity Asat, the maximum activity theoretically achievable by irradiating the target at this flux for an infinite time. The factor (1 − exp(−λt)) is the saturation fraction, which rises from 0 at t = 0 and approaches 1 asymptotically. After one product half-life, the saturation fraction is exactly 50%. After 3.32 half-lives, it reaches 90%. This diminishing-return relationship shapes the economics of isotope production: irradiating Mo-99 (T1/2 = 66 hr) targets for 5 to 7 days reaches 85 to 94% of saturation, while irradiating for 2 weeks adds only a small additional yield.
Production mode is used across nuclear medicine (Mo-99/Tc-99m generators, I-131, Lu-177, Y-90), industrial radiography (Ir-192, Co-60, Se-75), environmental tracing (Au-198 sediment tracers), and analytical chemistry (neutron activation analysis). Burnup mode covers the complementary problem: tracking the depletion of a target material, such as a boron control poison, a uranium fuel nuclide, or a neutron absorber used in shielding, where the quantity of interest is how much of the original material remains after a given irradiation period at a given flux.
Both calculations share the same mathematical structure: an exponential approach to a limiting value. In production, the approach is to saturation activity controlled by the product decay constant. In burnup, the approach is to complete depletion controlled by the effective burnup rate constant σφ. This calculator covers both modes with scientific-notation input for the flux and atom count, since these quantities routinely span 15 orders of magnitude across different applications.
📐 Formulas
📖 How to Use This Calculator
Steps
💡 Example Calculations
Example 1 - Au-197 Neutron Activation (3-Day Irradiation)
Au-197 target: 1020 atoms, σ = 98.7 barns, φ = 1013 n/cm2/s, T1/2(Au-198) = 2.695 days, t = 3 days
Example 2 - Co-60 Production (One-Year Reactor Irradiation)
Co-59 target: 6×1021 atoms, σ = 37.2 barns, φ = 5×1013 n/cm2/s, T1/2(Co-60) = 5.27 yr, t = 365 days
Example 3 - B-10 Control Poison Burnup (30-Day Irradiation)
B-10 absorber: N0 = 1022 atoms, σ = 3840 barns, φ = 1014 n/cm2/s, t = 30 days
❓ Frequently Asked Questions
🔗 Related Calculators
What is the isotope production formula A(t) = N·σ·φ·(1 - exp(-λt))?
This formula gives the radioactivity of a product isotope at time t during neutron irradiation. N is the number of target atoms, σ is the activation cross-section in cm² (1 barn = 10^-24 cm²), φ is the neutron flux in n/cm²/s, and λ = ln(2)/T1/2 is the decay constant of the product. The term (1 - exp(-λt)) is the saturation fraction, ranging from 0 at t=0 to 1 as t grows much larger than T1/2. At t = T1/2, the saturation fraction is exactly 0.5.
What is saturation activity and why does it matter?
Saturation activity A_sat = N·σ·φ is the maximum possible activity from a given target at a given flux. It equals the rate of production of the radioactive product at time zero, before any decay has occurred. At saturation, the production rate exactly equals the decay rate and the activity stops increasing. Saturation activity sets the ceiling for isotope production: to increase it you must increase the flux, the target mass, or use a target material with a larger cross-section.
How long does it take to reach 90% of saturation activity?
Setting the saturation fraction to 0.90 gives 1 - exp(-λt) = 0.90, so λt = ln(10) = 2.303, and t = 2.303/λ = 2.303 × T1/2 / ln(2) = 3.32 × T1/2. To reach 99% of saturation requires 6.64 half-lives. For a short-lived isotope like Mo-99 (T1/2 = 65.94 hr), 90% saturation takes about 9.2 days of continuous irradiation.
What is neutron burnup and how does it differ from isotope production?
Neutron burnup tracks the depletion of a target nuclide by neutron absorption without tracking radioactive ingrowth of a product. The burnup fraction B = 1 - exp(-σ·φ·t) measures what fraction of the original target atoms have been consumed. Burnup mode is appropriate when the product is stable or when you are only interested in fuel or poison depletion. Production mode is used when you care about the radioactivity that builds up in the product isotope.
What neutron flux is needed to produce 1 GBq of a medical isotope?
Rearranging A_sat = N·σ·φ: the required flux is φ = A_sat / (N·σ). For Au-198 production with 1 g of Au-197 (N = 3.07×10^21 atoms), σ = 98.7 barns = 9.87×10^-23 cm², and a target of 10 GBq saturation activity: φ = 10^10 / (3.07×10^21 × 9.87×10^-23) = 10^10 / 0.303 = 3.3×10^10 n/cm²/s. This is achievable in a low-flux research reactor.
How is Co-60 produced for industrial irradiators and cancer therapy?
Co-59 (natural cobalt) is loaded into a reactor and irradiated for 18 months to 3 years at a thermal neutron flux of about 3×10^13 n/cm²/s. The activation cross-section of Co-59 is 37.2 barns. Co-60 has a half-life of 5.27 years. Typical irradiation produces 10-20% of saturation activity, yielding 50-100 TBq per kilogram of cobalt target. The product is used in food irradiation, industrial gamma radiography, and Gamma Knife radiosurgery.
What is the activation cross-section and how is it different from the absorption cross-section?
The activation cross-section (also called the radiative capture cross-section, σ_γ) specifically quantifies the probability of neutron capture that produces a radioactive product via the (n,γ) reaction. The absorption cross-section σ_abs includes all reactions that remove a neutron from the beam: radiative capture plus fission (for fissile nuclei) plus other inelastic reactions. For non-fissile materials, σ_activation and σ_abs are nearly equal. For U-235, σ_abs = 683 b while σ_fission = 582 b and σ_capture = 101 b.
What is B-10 burnup and why is it important in reactor control?
B-10 (natural boron is 20% B-10) has a thermal neutron absorption cross-section of 3840 barns, one of the highest of any stable nuclide. Control rods and neutron poisons use B-10 to absorb neutrons and suppress reactivity. During reactor operation, B-10 is consumed at a rate proportional to σ·φ·N. After 1000 hours at a flux of 10^14 n/cm²/s, the burnup fraction is about 26%. Tracking B-10 depletion is essential for predicting control rod worth over a fuel cycle.
How do I find the atom count N from a known target mass?
Use N = (m × N_A) / A, where m is mass in grams, N_A = 6.022×10^23 atoms/mol (Avogadro constant), and A is the nuclide atomic mass in g/mol (approximately the mass number for most nuclides). For 1 mg of pure Mo-98 target (A = 97.91 g/mol): N = (0.001 × 6.022×10^23) / 97.91 = 6.15×10^18 atoms. Enter this as mantissa 6.15, exponent 18 in the calculator.
What neutron flux values are typical in different irradiation facilities?
Research reactors (e.g., NIST, ILL): thermal flux 10^14 to 2×10^15 n/cm²/s. Power reactor fuel center: 3-5×10^13 n/cm²/s. Medical cyclotron neutron beam: 10^8 to 10^12 n/cm²/s. Am-Be or Cf-252 neutron sources: 10^5 to 10^8 n/cm²/s. High-flux material test reactors (e.g., HFIR): up to 2×10^15 n/cm²/s in the reflector. The flux directly scales the production rate and burnup rate for a given target.
Can I use this calculator for fission product buildup?
Production mode can approximate the activity of a fission product if you treat fission as the source of the target atoms. However, for direct fission product inventory calculations, the proper approach is the Bateman equations including branching ratios and chain transitions. This calculator is most accurate for single-step activation reactions of the form target + n to product + gamma, where the product is the isotope of interest and no significant chain feeding occurs.
What is the relationship between saturation fraction and effective irradiation time?
The saturation fraction S(t) = 1 - exp(-λt) depends only on the ratio t / T1/2 of the irradiation time to the product half-life. At t = T1/2, S = 0.500. At t = 2×T1/2, S = 0.750. At t = 3×T1/2, S = 0.875. Each additional half-life adds half of the remaining gap to saturation. This diminishing return explains why irradiating beyond 3-4 half-lives is rarely economical, since you must double the irradiation time to close half the remaining gap.
Why does burnup use 1 - exp(-σ·φ·t) instead of a decay equation?
In burnup the target atoms are removed by neutron absorption, not by spontaneous radioactive decay. The removal rate is proportional to σ·φ·N(t), giving dN/dt = -σ·φ·N, whose solution is N(t) = N_0 × exp(-σ·φ·t). The product σ·φ plays the role of an effective decay constant. The key difference from radioactive decay is that σ·φ depends on the reactor operating condition and can be changed by adjusting the flux, whereas the radioactive decay constant λ is fixed by nuclear physics.