Warburg Impedance Calculator

Find the real part, imaginary part, and magnitude of the Warburg diffusion impedance from the Warburg coefficient and frequency.

📉 Warburg Impedance Calculator
Warburg coefficient (σ)
Ω·s−0.5
1500
Frequency (f)
Hz
0.0110000
Impedance magnitude |ZW|
—
Real part ZW'
—
−Imaginary part ZW''
—
Phase angle
—

📉 What is the Warburg Impedance Calculator?

Warburg impedance is the extra electrical impedance an electrochemical interface shows because the reacting species has to physically diffuse to the electrode surface, and this calculator computes it from the Warburg coefficient and frequency using the semi-infinite linear diffusion model.

Electrochemists use this to predict the low-frequency tail of a Nyquist plot before running an experiment, to sanity-check a fitted Warburg coefficient against raw data, and to see how strongly diffusion limits impedance at a specific frequency of interest.

A common misconception is that the Randles circuit alone (solution resistance plus charge-transfer resistance and double-layer capacitance) is a complete model of an electrochemical cell. It isn't when mass transport matters, real cells with significant diffusion limitations show an additional straight 45-degree line at low frequency that a plain Randles circuit cannot reproduce, and that line is exactly the Warburg element.

This calculator computes the real part ZW', the negative imaginary part −ZW'', the magnitude |ZW|, and the phase angle from your Warburg coefficient and frequency inputs, and plots how both components fall off with increasing frequency.

📐 Formula

ZW  =  σ · ω−0.5 · (1 − j)
ω = 2πf, angular frequency (rad/s)
ZW' = σ / √ω    −ZW'' = σ / √ω (equal in magnitude, giving a fixed 45° phase angle)
|ZW| = σ√2 / √ω
Example: σ=50 Ω·s−0.5, f=10 Hz → ZW'=6.308 Ω, −ZW''=6.308 Ω, |ZW|=8.921 Ω.

📖 How to Use This Calculator

Steps

1
Enter the Warburg coefficient. Type the Warburg coefficient sigma, usually obtained by fitting the low-frequency tail of a measured Nyquist plot.
2
Enter the frequency. Type the frequency at which you want to evaluate the Warburg impedance.
3
Read the impedance results and chart. The calculator reports Z', -Z'', magnitude, and the fixed 45-degree phase angle, and marks your frequency on the Z' and -Z'' versus frequency chart.

💡 Example Calculations

Example 1 — Moderate Diffusion Limitation at 10 Hz

σ=50 Ω·s−0.5, f=10 Hz

1
ω = 2π×10 = 62.832 rad/s, √ω = 7.927
2
ZW' = 50 / 7.927 = 6.308 Ω, −ZW'' = 6.308 Ω
|ZW| = 8.921 Ω, phase = −45.00°
Try this example →

Example 2 — Low Frequency, Diffusion Dominates

σ=100 Ω·s−0.5, f=1 Hz

1
ω = 2π×1 = 6.283 rad/s, √ω = 2.507
2
ZW' = 100 / 2.507 = 39.894 Ω, −ZW'' = 39.894 Ω
|ZW| = 56.419 Ω, phase = −45.00°
Try this example →

Example 3 — High Frequency, Diffusion Impedance Nearly Vanishes

σ=20 Ω·s−0.5, f=1000 Hz

1
ω = 2π×1000 = 6283.185 rad/s, √ω = 79.267
2
ZW' = 20 / 79.267 = 0.252 Ω, −ZW'' = 0.252 Ω
|ZW| = 0.357 Ω, phase = −45.00°
Try this example →

❓ Frequently Asked Questions

What is the Warburg impedance?+
The Warburg impedance models the extra impedance an electrochemical interface shows because reactant ions or molecules take time to diffuse to the electrode surface. For semi-infinite linear diffusion it is Zw = sigma * omega^(-1/2) * (1 - j), where sigma is the Warburg coefficient and omega is the angular frequency.
Why is the Warburg phase angle always 45 degrees?+
Because the real and imaginary parts of Zw are exactly equal at every frequency, sigma/sqrt(omega) for both, the ratio between them, and therefore the phase angle, stays fixed at -45 degrees regardless of sigma or frequency. This constant 45-degree line is how a Warburg element is recognized on a Nyquist plot.
What is the Warburg coefficient sigma?+
Sigma quantifies how strongly diffusion limits the impedance response. It depends on the diffusion coefficients and bulk concentrations of the oxidized and reduced species, the number of electrons transferred, and the electrode area, though in practice it is usually extracted by fitting measured impedance data rather than computed from those quantities directly.
Why does the earlier EIS Parameter Calculator not include the Warburg element?+
That calculator models the basic Randles circuit, solution resistance plus a parallel charge-transfer resistance and double-layer capacitance, which fits high and mid-frequency data well but ignores mass-transport limitations. This Warburg Impedance Calculator covers exactly the diffusion element that basic model leaves out.
How does frequency affect the Warburg impedance?+
Both the real and imaginary parts scale as 1/sqrt(f), so the Warburg impedance grows without bound as frequency drops toward zero and shrinks toward zero as frequency rises. This is why diffusion effects dominate the low-frequency tail of a Nyquist plot and disappear at high frequency.
What are typical units for the Warburg coefficient?+
Sigma is typically reported in ohms times seconds to the negative one-half power (ohm s^-0.5), sometimes written as ohm Hz^0.5 depending on convention. This calculator expects sigma in ohm s^-0.5 and frequency in hertz.
Can the Warburg element be finite instead of semi-infinite?+
Yes, a finite-length Warburg element (used for thin films or bounded diffusion) adds a hyperbolic tangent correction term that makes the impedance level off at low frequency instead of growing indefinitely. This calculator implements the simpler and more common semi-infinite case, valid when the diffusion layer never reaches a physical boundary within the timescale of the measurement.
What does a large Warburg impedance indicate about a cell?+
A large Warburg coefficient, and therefore a large Warburg impedance at a given frequency, points to slow mass transport, low reactant concentration, a small diffusion coefficient, or a restricted diffusion path. In batteries this often shows up as poor rate capability, the cell struggles to deliver current quickly because ions cannot reach the electrode surface fast enough.
How is the Warburg element combined with other circuit elements in practice?+
In a full Randles-with-Warburg model, the Warburg element sits in series with the charge-transfer resistance, and that series combination sits in parallel with the double-layer capacitance, with the solution resistance in series with the whole thing. Fitting software finds Rs, Rct, Cdl, and sigma together from the complete measured Nyquist plot, this calculator lets you evaluate the Warburg piece on its own once you know sigma.
What is the difference between a Warburg element and a constant phase element (CPE)?+
A Warburg element has a fixed 45-degree phase angle at every frequency, reflecting ideal semi-infinite diffusion. A constant phase element generalizes this with an adjustable exponent, letting the phase angle sit anywhere between 0 and 90 degrees, and is used to fit non-ideal, rough, or heterogeneous electrode surfaces that a pure Warburg element cannot capture exactly.

What is the Warburg impedance?

The Warburg impedance models the extra impedance an electrochemical interface shows because reactant ions or molecules take time to diffuse to the electrode surface. For semi-infinite linear diffusion it is Zw = sigma * omega^(-1/2) * (1 - j), where sigma is the Warburg coefficient and omega is the angular frequency.

Why is the Warburg phase angle always 45 degrees?

Because the real and imaginary parts of Zw are exactly equal at every frequency, sigma/sqrt(omega) for both, the ratio between them, and therefore the phase angle, stays fixed at -45 degrees regardless of sigma or frequency. This constant 45-degree line is how a Warburg element is recognized on a Nyquist plot.

What is the Warburg coefficient sigma?

Sigma quantifies how strongly diffusion limits the impedance response. It depends on the diffusion coefficients and bulk concentrations of the oxidized and reduced species, the number of electrons transferred, and the electrode area, though in practice it is usually extracted by fitting measured impedance data rather than computed from those quantities directly.

Why does the earlier EIS Parameter Calculator not include the Warburg element?

That calculator models the basic Randles circuit, solution resistance plus a parallel charge-transfer resistance and double-layer capacitance, which fits high and mid-frequency data well but ignores mass-transport limitations. This Warburg Impedance Calculator covers exactly the diffusion element that basic model leaves out.

How does frequency affect the Warburg impedance?

Both the real and imaginary parts scale as 1/sqrt(f), so the Warburg impedance grows without bound as frequency drops toward zero and shrinks toward zero as frequency rises. This is why diffusion effects dominate the low-frequency tail of a Nyquist plot and disappear at high frequency.

What are typical units for the Warburg coefficient?

Sigma is typically reported in ohms times seconds to the negative one-half power (ohm s^-0.5), sometimes written as ohm Hz^0.5 depending on convention. This calculator expects sigma in ohm s^-0.5 and frequency in hertz.

Can the Warburg element be finite instead of semi-infinite?

Yes, a finite-length Warburg element (used for thin films or bounded diffusion) adds a hyperbolic tangent correction term that makes the impedance level off at low frequency instead of growing indefinitely. This calculator implements the simpler and more common semi-infinite case, valid when the diffusion layer never reaches a physical boundary within the timescale of the measurement.

What does a large Warburg impedance indicate about a cell?

A large Warburg coefficient, and therefore a large Warburg impedance at a given frequency, points to slow mass transport, low reactant concentration, a small diffusion coefficient, or a restricted diffusion path. In batteries this often shows up as poor rate capability, the cell struggles to deliver current quickly because ions cannot reach the electrode surface fast enough.

How is the Warburg element combined with other circuit elements in practice?

In a full Randles-with-Warburg model, the Warburg element sits in series with the charge-transfer resistance, and that series combination sits in parallel with the double-layer capacitance, with the solution resistance in series with the whole thing. Fitting software finds Rs, Rct, Cdl, and sigma together from the complete measured Nyquist plot, this calculator lets you evaluate the Warburg piece on its own once you know sigma.

What is the difference between a Warburg element and a constant phase element (CPE)?

A Warburg element has a fixed 45-degree phase angle at every frequency, reflecting ideal semi-infinite diffusion. A constant phase element generalizes this with an adjustable exponent, letting the phase angle sit anywhere between 0 and 90 degrees, and is used to fit non-ideal, rough, or heterogeneous electrode surfaces that a pure Warburg element cannot capture exactly.