Acres Per Hour Calculator

Work out how many acres per hour a tractor and implement really cover, and how long a field of a given size will take.

🌱 Acres Per Hour Calculator
Unit system
Effective working width30.0 ft
ft
1120
Ground speed5.0 mph
mph
0.520
Field efficiency80 %
%
40100
Field size to cover160.0 acres
acres
12000
Effective work rate
—
Theoretical rate (100% efficiency)
—
Time to finish the field
—
Other unit system
—
Step-by-step working

🌱 What is Acres Per Hour?

Acres per hour is the field work rate of a tractor and implement combination, in other words how much ground the machine finishes in one hour of in-field time. Agricultural engineers call it field capacity, and they split it into two numbers. Theoretical field capacity assumes the implement works at its full rated width, at a constant speed, and never stops. Effective field capacity multiplies that ideal by a field efficiency factor, which absorbs everything the ideal ignores: headland turns, overlap between adjacent passes, refilling a seed hopper or spray tank, unloading grain, and the short pauses to adjust a setting or clear a blockage.

The number drives a surprising amount of practical decision making. A grain farmer sizing a new combine works backwards from the acres that must come off in a typical harvest window, then divides by the hours per day and the weather-safe days available to find the rate the machine has to hit. A custom operator quoting a spraying job needs the rate to convert an hourly cost into a per acre price that still leaves a margin on a small, awkward field. A contractor planning a week of mowing uses it to decide whether three sites fit into one day or need two. Even a smallholder deciding between a 6 ft and an 8 ft topper is really comparing acres per hour against purchase price.

The most common mistake is to treat the rated width of the implement as the working width. If you habitually overlap by a foot on a 30 ft header, your true working width is 29 ft and you have quietly given away three percent of your capacity on every pass, every day. The second most common mistake is optimism about efficiency. Very few operations sustain 90 percent. Long rectangular fields with wide implements and on-the-move unloading might reach 85, while small irregular paddocks with frequent refills routinely fall below 60. A third trap is counting road travel between fields inside the field time, which makes the calculated efficiency look far worse than the machine deserves.

This calculator does the conversion in both unit systems, shows the theoretical rate next to the effective rate so the cost of turning and overlap is visible as a number, and reports the hours and minutes needed to finish a field of the size you enter. The chart plots finish time against ground speed, which makes the diminishing return on speed obvious, and the comparison table lets you scan several speeds at once before you decide how hard to push.

📐 Formula

Acres/hr  =  (W × S × E) ÷ 8.25     Hours  =  Area ÷ Acres/hr
W = effective working width of the implement (ft), rated width minus overlap
S = ground speed held in the field (mph)
E = field efficiency as a decimal, so 80% is entered as 80 and used as 0.80
8.25 = 43,560 ft² per acre ÷ 5,280 ft travelled per hour at 1 mph
Metric: ha/hr = (W in m × S in km/h × E) ÷ 10
Conversion: 1 ha/hr = 2.4711 ac/hr, and 1 ac/hr = 0.4047 ha/hr
Example: 30 ft × 5 mph × 0.80 ÷ 8.25 = 14.55 acres per hour.

📖 How to Use This Calculator

Steps

1
Choose your unit system. Imperial gives feet, miles per hour and acres. Metric gives metres, kilometres per hour and hectares, and switching converts the values already typed.
2
Enter width and speed. Use the effective working width after deducting overlap, and the ground speed you genuinely hold rather than the top speed on the dash.
3
Set the field efficiency. Typical values are 60 to 70 percent for planters, 70 to 85 percent for tillage and 65 to 80 percent for combines.
4
Read the rate and the finish time. You get effective acres per hour, the theoretical rate, the equivalent in the other unit system, and the hours and minutes for your field.

💡 Example Calculations

Example 1 — Combine Harvesting a Quarter Section

30 ft header, 5 mph, 80% efficiency, 160 acre field

1
Theoretical rate = 30 × 5 ÷ 8.25 = 18.18 acres per hour.
2
Effective rate = 18.18 × 0.80 = 14.55 acres per hour, so turning and unloading cost 3.64 acres every hour.
3
Time to finish = 160 ÷ 14.55 = 11.00 hours of in-field time, which is 5.89 ha per hour in metric terms.
Effective rate 14.55 ac/hr, finish time 11 h 00 m (5.89 ha/hr)
Try this example →

Example 2 — Contract Mowing a Small Site

12 ft flail mower, 4 mph, 85% efficiency, 40 acre parkland

1
Theoretical rate = 12 × 4 ÷ 8.25 = 5.82 acres per hour.
2
Effective rate = 5.82 × 0.85 = 4.95 acres per hour, because open parkland allows long uninterrupted runs.
3
Time to finish = 40 ÷ 4.95 = 8.09 hours, so the job fills a full day and cannot be quoted as a half day.
Effective rate 4.95 ac/hr, finish time 8 h 05 m (2.00 ha/hr)
Try this example →

Example 3 — Self-Propelled Sprayer on a Large Block

60 ft boom, 12 mph, 65% efficiency, 500 acre block

1
Theoretical rate = 60 × 12 ÷ 8.25 = 87.27 acres per hour.
2
Effective rate = 87.27 × 0.65 = 56.73 acres per hour, because tank refills dominate the lost time on a sprayer.
3
Time to finish = 500 ÷ 56.73 = 8.81 hours, so the block clears inside one long spray day if the wind holds.
Effective rate 56.73 ac/hr, finish time 8 h 49 m (22.96 ha/hr)
Try this example →

Example 4 — Metric Seed Drill

6 m drill, 8 km/h, 75% efficiency, 20 hectare field

1
Theoretical rate = 6 × 8 ÷ 10 = 4.80 hectares per hour.
2
Effective rate = 4.80 × 0.75 = 3.60 hectares per hour, with seed and fertiliser refills taking the missing quarter.
3
Time to finish = 20 ÷ 3.60 = 5.56 hours, and the same rate reads as 8.90 acres per hour in imperial units.
Effective rate 3.60 ha/hr, finish time 5 h 33 m (8.90 ac/hr)
Try this example →

❓ Frequently Asked Questions

What is the formula for acres per hour?+
Acres per hour = working width in feet times ground speed in mph times field efficiency, all divided by 8.25. The 8.25 comes from 43,560 square feet in an acre divided by 5,280 feet travelled per hour at one mph. A 30 ft implement at 5 mph and 80 percent efficiency covers 14.55 acres per hour.
Where does the number 8.25 come from?+
One mile per hour moves the machine 5,280 feet in an hour, so one foot of width sweeps 5,280 square feet per hour. An acre is 43,560 square feet, and 43,560 divided by 5,280 is 8.25. Dividing width times speed by 8.25 therefore converts feet and mph straight into acres per hour with no other steps.
What is field efficiency in farming?+
Field efficiency is the share of clock time the implement spends actually working at full width. It absorbs headland turns, overlap between passes, filling and unloading stops, and short adjustments. Typical values run 60 to 70 percent for planters, 70 to 85 percent for tillage and 65 to 80 percent for combines.
What is the difference between theoretical and effective field capacity?+
Theoretical field capacity assumes the implement works at its full rated width, at a constant speed, and never stops. Effective field capacity multiplies that ideal by field efficiency, so it reflects the acres you actually finish. On a typical harvest day the gap between the two is a quarter of the working time.
How do I calculate hectares per hour instead of acres?+
Use hectares per hour = width in metres times speed in km/h times efficiency divided by 10. A 6 m drill at 8 km/h and 75 percent efficiency covers 3.6 hectares per hour. Switch this calculator to metric mode and it converts the width, speed and area figures you have already typed.
How long will it take to cover my field?+
Divide the field size by the effective rate. A 160 acre field worked at 14.55 acres per hour takes 11.0 hours of in-field time. That figure excludes road travel between fields, machine setup and meal breaks, so a realistic working day rarely delivers the full theoretical output.
What is a typical field efficiency for a combine harvester?+
Most combines run between 65 and 80 percent. Unloading grain on the move keeps the figure at the top of that band, while stopping to unload into a stationary trailer, working lodged crop, or repeatedly slowing for wet patches will push it down towards 60 percent or below.
Does increasing speed always increase acres per hour?+
Arithmetically yes, but only until quality collapses. Planters lose seed spacing accuracy above roughly 6 mph without high speed meters, sprayers suffer boom bounce and poor coverage, and combines start losing grain over the sieves. Past that point the extra acres cost more in lost yield than they earn in saved hours.
Should I use the full implement width in the calculation?+
Use the effective working width, which is the rated width minus your habitual overlap. GPS guidance cuts overlap to a few centimetres, while passes lined up by eye commonly overlap 5 to 10 percent. That overlap is a direct and permanent loss of capacity on every single pass.
How do I turn acres per hour into a custom rate per acre?+
Divide your total hourly cost, including fuel, repairs, depreciation and labour, by the effective acres per hour. If a machine costs 180 per hour to run and covers 14.55 acres per hour, the break-even charge is about 12.37 per acre. Add your margin and a loading for small or awkward fields on top.
Why is my real work rate lower than the calculator says?+
The usual causes are an optimistic efficiency figure, forgetting overlap when entering the width, and counting road travel or breaks inside the field time. Time one full field with a stopwatch, divide the acres by the hours, then back-calculate your own efficiency and reuse that number for future planning.
Can I use this for mowing, spraying or snow clearing?+
Yes. The geometry is identical for any machine that sweeps a fixed width across the ground at a steady speed, so it works for lawn mowing contractors, boom sprayers, roadside flails, verge cutters and even snow ploughs. Only the sensible field efficiency value changes between those jobs.
How many acres per hour does a 12 ft mower cover?+
At 4 mph and 85 percent efficiency, a 12 ft mower covers 12 times 4 times 0.85 divided by 8.25, which is 4.95 acres per hour. Raising the speed to 6 mph lifts that to 7.42 acres per hour, provided the ground is smooth enough to hold the extra speed safely.
Does field shape change the answer?+
Field shape does not change the formula, but it changes the efficiency you should enter. Long rectangular fields need few turns per acre, so efficiency stays high. Small, triangular or obstacle-filled fields force many short passes and headland turns, and can drop a machine that manages 85 percent elsewhere down to 55 percent.

What is the formula for acres per hour?

Acres per hour = working width in feet times ground speed in mph times field efficiency, all divided by 8.25. The 8.25 comes from 43,560 square feet in an acre divided by 5,280 feet travelled per hour at one mph. A 30 ft implement at 5 mph and 80 percent efficiency covers 14.55 acres per hour.

Where does the number 8.25 come from?

One mile per hour moves the machine 5,280 feet in an hour, so one foot of width sweeps 5,280 square feet per hour. An acre is 43,560 square feet, and 43,560 divided by 5,280 is 8.25. Dividing width times speed by 8.25 therefore converts feet and mph straight into acres per hour.

What is field efficiency?

Field efficiency is the share of clock time the implement spends actually working at full width. It absorbs headland turns, overlap between passes, filling and unloading stops, and short adjustments. Typical values run 60 to 70 percent for planters, 70 to 85 percent for tillage and 65 to 80 percent for combines.

What is the difference between theoretical and effective field capacity?

Theoretical field capacity assumes the implement works at full rated width, at constant speed, with no stops. Effective field capacity multiplies that by field efficiency, so it reflects the acres you actually finish. The gap is often a quarter of the working day.

How do I calculate hectares per hour instead?

Use hectares per hour = width in metres times speed in km/h times efficiency divided by 10. A 6 m drill at 8 km/h and 75 percent efficiency covers 3.6 ha per hour. Switch the calculator to metric mode and it converts your existing figures for you.

How long will it take to cover my field?

Divide the field size by the effective rate. A 160 acre field at 14.55 acres per hour takes 11.0 hours of in-field time. Remember that this excludes road travel between fields, so a working day rarely delivers the full figure.

What is a typical field efficiency for a combine harvester?

Most combines run between 65 and 80 percent. Grain tank unloading on the move keeps the number high, while frequent stops to unload into a stationary trailer, lodged crop or wet patches will push it to 60 percent or below.

Does increasing speed always increase acres per hour?

Mathematically yes, but only up to the point where quality collapses. Planters lose seed spacing accuracy above about 6 mph unless fitted with high speed meters, sprayers lose coverage as boom bounce grows, and combines start losing grain over the sieves. Past that point the extra acres cost more than they earn.

Should I use the full implement width in the calculation?

Use the effective working width, which is the rated width minus your habitual overlap. Guidance systems cut overlap to a few centimetres, while eyeballed passes commonly overlap 5 to 10 percent, and that overlap is a direct loss of capacity.

How do I turn acres per hour into a custom rate per acre?

Divide your total hourly cost, which includes fuel, repairs, depreciation and labour, by the effective acres per hour. If the machine costs 180 per hour to run and covers 14.55 acres per hour, the break-even charge is about 12.37 per acre before profit.

Why is my real work rate lower than the calculator says?

The usual causes are an optimistic efficiency figure, forgetting overlap when entering width, and counting road travel or lunch inside the field time. Time one full field with a stopwatch, then back-calculate your own efficiency and reuse that number.

Can I use this for mowing, spraying or snow clearing?

Yes. The geometry is identical for any machine that sweeps a fixed width across ground at a steady speed, so it works for lawn mowing contractors, boom sprayers, roadside flails and even snow ploughs. Only the sensible efficiency value changes.