Angular Resolution Calculator

Enter aperture diameter and wavelength to find the diffraction-limited angular resolution of any telescope, or find the aperture needed to reach a target resolution.

🔭 Angular Resolution Calculator
Telescope or Instrument Preset
Aperture Diameter (D)
Target Angular Resolution
arcsec
Wavelength (λ)
Angular Resolution θ (Rayleigh Criterion)
In Radians
In Milliarcseconds (mas)
Required Aperture Diameter
In Metres

🔭 What Is Angular Resolution?

Angular resolution is the smallest angular separation between two point sources that a telescope or optical system can distinguish as separate objects. Below this limit, the two sources blur together into a single unresolved blob, regardless of how much magnification is applied. Angular resolution is set by the wave nature of light through the phenomenon of diffraction: when light passes through a circular aperture, it spreads into a central bright disk (the Airy disk) surrounded by rings. Two nearby stars can only be resolved if their Airy disks are sufficiently separated.

The Rayleigh criterion defines angular resolution as the condition where the central maximum of one diffraction pattern falls on the first minimum of the other. For a circular aperture this gives the formula θ = 1.22λ/D, where λ is the wavelength of observation and D is the aperture diameter. The factor 1.22 comes from the mathematics of circular aperture diffraction (the first zero of the Bessel function J1 at argument 1.22π). Smaller apertures and longer wavelengths both produce worse resolution (larger θ), while larger apertures and shorter wavelengths give finer resolution.

Real telescope performance depends on more than just aperture. Ground-based optical telescopes are typically limited by atmospheric seeing, turbulence in Earth's atmosphere that blurs stellar images to about 0.5 to 2 arcseconds regardless of aperture. A 10-metre telescope has a diffraction limit of only 0.014 arcseconds at 550 nm, but without adaptive optics it sees no better than a 20-centimetre amateur telescope at the same site. Adaptive optics systems measure and correct atmospheric distortions in real time using deformable mirrors, allowing large ground-based telescopes to approach their diffraction limits. Space telescopes like Hubble and JWST operate entirely above the atmosphere and achieve close to their theoretical Rayleigh limits.

Radio astronomy extends the concept to much longer wavelengths, where individual dishes would need to be continent-sized to match optical resolution. Very long baseline interferometry (VLBI) uses widely separated radio telescopes that observe simultaneously, effectively creating a telescope as large as their separation. The Event Horizon Telescope used radio dishes across six continents, spanning nearly Earth's full diameter, to achieve a resolution of about 20 microarcseconds at 1.3 mm, allowing the first direct images of black hole shadows in M87 and our own galactic centre.

📐 Formula

θ  =  1.22 × λ / D
θ = angular resolution in radians (convert to arcseconds by multiplying by 206,265)
λ = wavelength of observation (metres; 1 nm = 10−9 m, 1 μm = 10−6 m)
D = aperture diameter of the telescope or lens (metres)
1.22 = Rayleigh factor for circular apertures (first zero of Bessel function J1)
Reverse mode: D = 1.22 × λ / θ (find required aperture for a target resolution)
Conversion: 1 radian = 206,265 arcseconds = 3,438 arcminutes = 57.3 degrees
Example: Human eye (D = 5 mm, λ = 550 nm): θ = 1.22 × 550 × 10−9 / 5 × 10−3 = 1.342 × 10−4 rad = 27.7 arcsec

📖 How to Use This Calculator

Steps

1
Select a telescope preset or enter custom aperture — Choose a preset instrument (Human Eye, Hubble, JWST, VLA, EHT) to auto-fill aperture and wavelength, or enter your own values in the mode you want.
2
Choose calculation mode — Use Aperture to Resolution mode to compute the angular resolution from a given aperture and wavelength. Use Resolution to Aperture mode to find the minimum aperture needed to achieve a target resolution.
3
Enter aperture and wavelength (mode 1) — In Aperture to Resolution mode, enter the telescope aperture diameter and select the unit (mm, cm, m, or km). Then enter the observation wavelength and select the unit (nm, um, mm, cm, m).
4
Enter target resolution and wavelength (mode 2) — In Resolution to Aperture mode, enter the desired angular resolution in arcseconds and the observation wavelength. The calculator returns the minimum aperture needed.
5
Read the angular resolution in appropriate units — The calculator auto-scales the result between microarcseconds, milliarcseconds, arcseconds, arcminutes, and degrees depending on the magnitude of the result.

💡 Example Calculations

Example 1 — Human Eye (Aperture to Resolution)

Dark-adapted eye: aperture D = 5 mm, green light λ = 550 nm

1
Convert: λ = 550 nm = 550 × 10−9 m, D = 5 mm = 0.005 m
2
Apply Rayleigh criterion: θ = 1.22 × 550 × 10−9 / 0.005 = 1.342 × 10−4 radians
3
Convert to arcseconds: 1.342 × 10−4 × 206,265 = 27.68 arcseconds = 0.46 arcminutes
4
In practice, the eye resolves about 1 arcminute due to the spacing of cone photoreceptors in the fovea (each about 2 μm wide), which is coarser than the diffraction limit set by the pupil aperture.
Angular Resolution = 27.6808 arcsec (1.3420 × 10−4 rad, 27,680.8 mas)
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Example 2 — Hubble Space Telescope (Aperture to Resolution)

HST: aperture D = 2.4 m, blue-green light λ = 500 nm

1
Convert: λ = 500 × 10−9 m, D = 2.4 m
2
Rayleigh criterion: θ = 1.22 × 500 × 10−9 / 2.4 = 2.5417 × 10−7 radians
3
In arcseconds: 2.5417 × 10−7 × 206,265 = 0.05243 arcsec = 52.43 mas. This is about 530 times finer than the unaided eye.
4
HST achieves close to this diffraction limit in space. From the ground, atmospheric seeing would limit a 2.4 m telescope to about 0.5 to 1 arcsecond without adaptive optics, roughly 10 to 20 times worse than the diffraction limit.
Angular Resolution = 52.4257 mas (0.052426 arcsec, 2.5417 × 10−7 rad)
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Example 3 — Required Aperture to Resolve a Binary Star (Resolution to Aperture)

Target: resolve two stars separated by 0.1 arcseconds at optical wavelength 500 nm

1
Convert target: 0.1 arcsec = 0.1 / 206,265 = 4.848 × 10−7 radians
2
Reverse Rayleigh formula: D = 1.22 × λ / θ = 1.22 × 500 × 10−9 / 4.848 × 10−7 = 1.26 m
3
A telescope with a 1.26 m aperture is the minimum needed to diffraction-limit resolve this binary system at 500 nm. In practice, seeing or adaptive optics performance determines whether this is achievable.
4
Most professional telescopes (2 m to 10 m) can resolve 0.1 arcsec pairs with adaptive optics. Space telescopes like HST (D = 2.4 m, limit 0.052 arcsec) can resolve them directly without AO.
Required Aperture = 1.26 m (resolves 0.1 arcsec at 500 nm)
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❓ Frequently Asked Questions

What is the Rayleigh criterion and where does the 1.22 factor come from?+
The Rayleigh criterion defines two point sources as just resolved when the central maximum of one diffraction pattern coincides with the first dark ring of the other. For a circular aperture, this condition corresponds to the first zero of the Bessel function J1, which occurs at an argument of approximately 1.22pi. This gives the angular separation theta = 1.22 lambda / D radians. For a rectangular slit the factor is 1.0 (not 1.22), which is the simpler form often used in introductory physics.
Why does atmospheric seeing limit ground-based telescopes?+
Earth's atmosphere contains turbulent cells of air at different temperatures and thus different refractive indices. These cells act like moving lenses that distort the wavefront of incoming starlight. A star that should appear as a tiny diffraction disk instead dances around and blurs into a seeing disk of 0.5 to 2 arcseconds. For a 1-meter aperture, the diffraction limit is 0.13 arcsec at 550 nm, much finer than typical seeing. Adaptive optics systems measure the wavefront distortion 100 to 1,000 times per second and correct it with a deformable mirror, recovering much of the diffraction-limited performance.
How do radio interferometers achieve high angular resolution?+
Very long baseline interferometry (VLBI) uses widely separated radio telescopes that observe the same source simultaneously and record the signals with precise atomic clocks. The signals are later combined digitally, creating an interferometer with a baseline equal to the separation between telescopes. Since resolution = 1.22 lambda / D, using a 10,000 km baseline at 1.3 mm wavelength gives 32 microarcseconds, similar to or better than optical space telescopes at much longer wavelengths. The EHT effectively creates an Earth-sized radio telescope this way.
What is the angular resolution of JWST?+
JWST has a hexagonal primary mirror of 6.5 m effective diameter and observes from 0.6 to 28 microns. At 2 microns (near-infrared), the Rayleigh criterion gives theta = 1.22 x 2e-6 / 6.5 = 3.75e-7 radians = 0.077 arcseconds = 77 mas. JWST is above the atmosphere and achieves close to this diffraction limit. Its resolution is about 360 times better than the unaided eye and comparable to Hubble at optical wavelengths, despite JWST's longer infrared wavelengths being compensated by its larger mirror.
What is the angular resolution of the human eye?+
With a dark-adapted pupil of about 5 mm diameter and peak sensitivity near 550 nm, the Rayleigh criterion gives about 27.7 arcseconds (0.46 arcminutes) for the human eye. However, empirical measurements of visual acuity give a resolving power of about 1 arcminute for black and white gratings, because the photoreceptor spacing in the fovea (cones about 2 to 3 micrometres apart) sets a coarser limit than diffraction. The best human visual acuity is achieved in bright light when the pupil is smaller (about 2 mm) but contrast is high.
How is angular resolution related to the size of objects that can be distinguished?+
Angular resolution theta (in radians) relates to physical separation s at distance d by s = d x theta. For example, with a resolution of 0.05 arcsec (like Hubble) and an object at 1 kiloparsec (3.086e19 m), the minimum resolvable physical size is s = 3.086e19 x (0.05 / 206265) = 7.48e12 m = 50 AU. At 10 Mpc (a nearby galaxy cluster), Hubble resolves structures of about 700 parsecs or 2,300 light-years. VLBI at 20 microarcseconds can resolve structures of about 0.1 light-year at 1 kiloparsec.
What is the difference between angular resolution and field of view?+
Angular resolution is the smallest detail the telescope can see, set by diffraction (and aperture). Field of view is the total area of sky visible in one pointing, determined by the focal length and detector size. A large telescope has excellent resolution but often a narrow field of view (it zooms in on a tiny patch of sky). Wide-field survey telescopes trade resolution for field of view by using shorter focal lengths. Modern instruments like the Rubin Observatory LSST achieve both relatively high resolution (0.2 arcsec per pixel) and a large 9.6 square degree field of view by combining a large mirror with a huge mosaic camera.
Can the Rayleigh criterion be beaten?+
Yes, through several techniques. Speckle interferometry combines many short-exposure images to extract high-resolution information hidden in atmospheric speckles. Lucky imaging selects the rare moments of atmospheric calm. Interferometric techniques like intensity interferometry or amplitude interferometry combine signals from separated apertures. Super-resolution algorithms applied to many dithered images can extract sub-pixel information. In the lab, near-field scanning optical microscopy (NSOM) can beat the diffraction limit by using sub-wavelength probe tips. However, for astronomical observations of point sources, the Rayleigh criterion remains the fundamental practical limit for standard imaging.
Why are X-ray telescopes harder to build than optical telescopes?+
X-rays (wavelengths 0.01 to 10 nm) are so energetic that they pass straight through normal mirrors instead of reflecting. X-ray telescopes use grazing-incidence mirrors where X-rays hit a curved surface at very shallow angles (like a stone skipping water) and are redirected onto a detector. These mirrors must be polished to atomic smoothness over their full surface. Despite the shorter wavelength (which should give finer resolution), practical X-ray telescopes like Chandra achieve about 0.5 arcsecond resolution, limited by mirror figure errors rather than diffraction. Future X-ray interferometers have been proposed to reach sub-milliarcsecond resolution.
How does aperture affect both resolution and light-gathering power?+
Aperture affects both resolution (theta = 1.22 lambda / D, linear in D) and light-gathering power (proportional to D squared, since light-collecting area scales as D squared). Doubling the aperture halves the resolvable angle and quadruples the light-gathering ability. This is why large telescopes are doubly advantageous: they can see fainter objects and distinguish finer details simultaneously. A 10-metre telescope collects 100 times more light than a 1-metre telescope and resolves details 10 times finer, explaining the push toward ever-larger mirror diameters in next-generation observatories like the Extremely Large Telescope (39 m).

What is the Rayleigh criterion for angular resolution?

The Rayleigh criterion states that two point sources are just resolved when the central maximum of one diffraction pattern falls on the first minimum of the other. For a circular aperture this gives angular resolution theta = 1.22 lambda / D, where lambda is the wavelength and D is the aperture diameter. The factor 1.22 comes from the first zero of the Bessel function J1 at radius 1.22 pi, which arises for circular (not slit) apertures.

What limits telescope resolution in practice?

For ground-based optical telescopes, the main limitation is atmospheric seeing: turbulence in the atmosphere blurs star images to about 0.5 to 2 arcseconds, far larger than the diffraction limit for large telescopes. A 2-meter telescope has a diffraction limit of 0.063 arcseconds at 500 nm but is typically limited to 1 arcsecond by seeing. Adaptive optics systems correct for atmospheric turbulence in real time and allow large telescopes to approach their diffraction limit. Space telescopes like Hubble and JWST are seeing-limited only by their own optics.

How does wavelength affect angular resolution?

Angular resolution is directly proportional to wavelength: doubling the wavelength doubles the angular resolution (makes it twice as coarse). Radio telescopes operating at centimetre or metre wavelengths need enormous apertures or interferometric baselines to match the resolution of optical telescopes. The Event Horizon Telescope uses 1.3 mm wavelength (short for radio) and a 10,000 km baseline to achieve microarcsecond resolution comparable to space-based optical telescopes.

What is the angular resolution of the human eye?

The human eye has a pupil diameter of about 5 mm in dim light. At 550 nm (green, peak sensitivity), the Rayleigh criterion gives theta = 1.22 x 550e-9 / 5e-3 = 1.34e-4 radians = 27.7 arcseconds = 0.46 arcminutes. This matches the empirical limit of about 1 arcminute for two lines to appear distinct, with the difference due to the finite size of photoreceptors (cones) in the fovea rather than pure diffraction.

How does Hubble's angular resolution compare to the human eye?

Hubble (D = 2.4 m, lambda = 500 nm) has a diffraction-limited resolution of about 0.05 arcseconds, roughly 550 times finer than the unaided eye's limit of 27.7 arcseconds. This means Hubble can resolve details 550 times smaller than the eye can, allowing it to see galaxies billions of light-years away in stunning detail and to resolve the orbits of stars around the Milky Way's central black hole.

What is the angular resolution of the Event Horizon Telescope?

The EHT uses very long baseline interferometry at 1.3 mm wavelength with a maximum baseline of about 10,000 km (approximately Earth's diameter). This gives an angular resolution of about 1.22 x 1.3e-3 / 1e7 = 1.59e-10 radians = 32.7 microarcseconds. The EHT used this resolution to image the shadow of the supermassive black hole M87 (angular size about 40 microarcseconds) and later Sgr A*, the Milky Way's central black hole.

Why do radio telescopes need to be so large?

Radio wavelengths (centimetres to metres) are 10,000 to 1,000,000 times longer than optical wavelengths (hundreds of nanometres). Since angular resolution = 1.22 lambda / D, achieving 1 arcsecond resolution at 21 cm requires D = 1.22 x 0.21 / (1 / 206265) = 52.7 km. This is why the VLA uses a 36 km baseline and the EHT uses a 10,000 km baseline via interferometry: a single dish of comparable size would be impractical.

What is the difference between resolution and magnification?

Magnification increases the apparent size of an object but cannot reveal detail beyond the telescope's angular resolution limit. If two stars are separated by less than theta = 1.22 lambda / D, no amount of magnification will make them appear as separate points. Resolution is the fundamental limit set by diffraction, while magnification is about how large the image appears. A pair of binoculars with high magnification but small aperture will show blurry images of objects that a smaller magnification but larger aperture telescope resolves sharply.

How do I calculate the aperture needed to resolve a given angular separation?

Rearranging the Rayleigh criterion: D = 1.22 lambda / theta. For example, to resolve two stars separated by 0.1 arcseconds at 500 nm wavelength, theta = 0.1 x pi / (180 x 3600) = 4.848e-7 radians, so D = 1.22 x 500e-9 / 4.848e-7 = 1.26 m. A telescope with aperture 1.26 m or larger (in space or with adaptive optics) would just resolve this binary system at optical wavelengths.

What is the angular resolution of JWST at infrared wavelengths?

JWST has a primary mirror diameter of 6.5 m and operates primarily at near-infrared wavelengths (0.6 to 28 microns). At 2 microns, the Rayleigh criterion gives theta = 1.22 x 2e-6 / 6.5 = 3.75e-7 radians = 0.077 arcseconds. This is about 360 times finer than the unaided eye, and roughly comparable to Hubble at optical wavelengths despite operating at longer wavelengths, because JWST's mirror is nearly 3 times larger than Hubble's.