Electric Field Between Parallel Plates Calculator

Find the electric field, capacitance, stored charge, and stored energy of a parallel-plate capacitor from its voltage, plate separation, and area.

🔌 Electric Field Between Parallel Plates Calculator
V
mm
cm²
Electric field (E)
—
Capacitance (C)
—
Charge (Q)
—
Stored energy (U)
—
Step-by-step working

🔌 What is the Electric Field Between Parallel Plates Calculator?

The Electric Field Between Parallel Plates Calculator finds the uniform electric field, capacitance, stored charge, stored energy, and field energy density of an idealized parallel-plate capacitor from its applied voltage, plate separation, plate area, and dielectric material.

Electrical engineering and physics students use this calculation to build intuition for how capacitors store charge and energy, understand the relationship between field strength and breakdown risk in high-voltage insulation design, and connect the abstract concept of an electric field to concrete, measurable quantities like capacitance and stored energy.

A common point of confusion is that the field E = V/d depends only on voltage and separation, not on the plate area, while capacitance, charge, and stored energy all scale with plate area. Doubling the plate area at fixed voltage and separation leaves the field unchanged but doubles the capacitance, charge, and stored energy.

This calculator computes all of these quantities together from one consistent set of inputs, and plots how the field strength changes as the plate separation varies, so you can see the inverse relationship directly.

📐 Formula

E = V/d      C = ε0εrA/d      U = ½CV²
E = electric field (V/m), V = voltage (V), d = plate separation (m)
C = capacitance (F), A = plate area (m²), ε0 = 8.854×10⁻¹² F/m
Q = CV (charge), u = ½ε0εrE² (energy density, J/m³)
Example: V=100V, d=1mm, A=10cm², εr=1 → E≈0.1 MV/m, C≈8.854 pF, Q≈0.8854 nC, U≈44.271 nJ.

📖 How to Use This Calculator

Steps

1
Enter the voltage and separation. Type V, the voltage across the plates, and d, the gap between them.
2
Enter the plate area and dielectric. Type the plate area and the relative permittivity of the material between the plates (1 for vacuum or air).
3
Read the results. The calculator reports the electric field, capacitance, stored charge, and stored energy.

💡 Example Calculations

Example 1 — Air-Gap Capacitor

V=100V, d=1mm, A=10cm², εr=1 (air)

1
E = 100 / 0.001 = 0.1 MV/m (100,000 V/m)
2
C = 8.854×10⁻¹² × 1 × 0.001 / 0.001 = 8.854 pF
3
Q = CV = 0.8854 nC, U = ½CV² = 44.271 nJ
E = 0.1 MV/m, C = 8.854 pF, U = 44.271 nJ
Try this example →

Example 2 — Small Ceramic Capacitor

V=12V, d=0.1mm, A=1cm², εr=4.5 (ceramic)

1
E = 12 / 0.0001 = 0.12 MV/m (120,000 V/m)
2
C = 8.854×10⁻¹² × 4.5 × 0.0001 / 0.0001 = 39.844 pF
3
Q = CV = 0.4781 nC, U = ½CV² = 2.8688 nJ
E = 0.12 MV/m, C = 39.844 pF, U = 2.8688 nJ
Try this example →

Example 3 — High-Voltage Air Gap

V=5000V, d=5mm, A=100cm², εr=1 (air)

1
E = 5,000 / 0.005 = 1 MV/m (1,000,000 V/m)
2
C = 8.854×10⁻¹² × 1 × 0.01 / 0.005 = 17.708 pF
3
Q = CV = 88.5419 nC, U = ½CV² = 221.3547 µJ
E = 1 MV/m, C = 17.708 pF, Q = 88.5419 nC, U ≈ 221.3547 µJ
Try this example →

❓ Frequently Asked Questions

What is the electric field between parallel plates?+
The electric field between two parallel plates carrying opposite charge and separated by a uniform gap is E = V/d, where V is the voltage across the plates and d is the separation distance. This uniform field approximation holds well when the plate area is large compared to the gap.
What is the formula for parallel-plate capacitance?+
C = epsilon_0 x epsilon_r x A / d, where epsilon_0 is the permittivity of free space, epsilon_r is the dielectric's relative permittivity, A is the plate area, and d is the separation. Capacitance increases with larger plate area or smaller separation, and with a higher-permittivity dielectric.
How is the stored charge related to capacitance?+
The charge stored on each plate is Q = CV, directly proportional to both the capacitance and the applied voltage. This is the same fundamental relationship that defines capacitance for any capacitor geometry, not just parallel plates.
How is energy stored in a capacitor calculated?+
The energy stored in a charged capacitor is U = 0.5 x C x V^2 (equivalently 0.5 x Q x V or 0.5 x Q^2/C). This represents the work done to charge the capacitor against the growing electric field between its plates.
What is energy density in the field between the plates?+
Energy density u = 0.5 x epsilon_0 x epsilon_r x E^2 is the energy stored per unit volume of the field region, it depends only on the field strength and the dielectric, making it a useful measure for comparing energy storage efficiency independent of the specific plate dimensions.
Why does a smaller gap increase the field for the same voltage?+
Since E = V/d, for a fixed voltage the field is inversely proportional to the separation distance, halving the gap concentrates the same potential difference over half the distance, doubling the field strength. This is why capacitors with very thin dielectrics can achieve very high fields at modest voltages.
What is relative permittivity (dielectric constant)?+
Relative permittivity epsilon_r describes how much more a material can be polarized by an electric field compared to vacuum (epsilon_r = 1). Common dielectrics used in real capacitors, ceramics, polymers, tantalum oxide, have epsilon_r values ranging from around 2 up to several thousand for high-permittivity ceramics.
What limits how high the electric field can be before breakdown?+
Every dielectric material has a maximum electric field, its dielectric strength, beyond which it breaks down electrically (arcing or permanent damage). Air breaks down at roughly 3 MV/m at standard conditions, solid dielectrics used in real capacitors typically sustain far higher fields, which is part of why they allow much higher capacitance and voltage ratings in a compact size.
Does plate shape matter for this calculation?+
This calculator uses the idealized infinite-parallel-plate approximation, which depends only on total plate area, not shape, for real finite plates the field near the edges (fringing field) differs from the uniform interior field, becoming more significant when the separation is not small compared to the plate dimensions.
What units does this calculator use?+
Voltage is in volts, plate separation in millimeters, and plate area in square centimeters. Results are reported in MV/m (electric field), picofarads (capacitance), nanocoulombs (charge), nanojoules or microjoules (energy), and joules per cubic meter (energy density).

What is the electric field between parallel plates?

The electric field between two parallel plates carrying opposite charge and separated by a uniform gap is E = V/d, where V is the voltage across the plates and d is the separation distance. This uniform field approximation holds well when the plate area is large compared to the gap.

What is the formula for parallel-plate capacitance?

C = epsilon_0 x epsilon_r x A / d, where epsilon_0 is the permittivity of free space, epsilon_r is the dielectric's relative permittivity, A is the plate area, and d is the separation. Capacitance increases with larger plate area or smaller separation, and with a higher-permittivity dielectric.

How is the stored charge related to capacitance?

The charge stored on each plate is Q = CV, directly proportional to both the capacitance and the applied voltage. This is the same fundamental relationship that defines capacitance for any capacitor geometry, not just parallel plates.

How is energy stored in a capacitor calculated?

The energy stored in a charged capacitor is U = 0.5 x C x V^2 (equivalently 0.5 x Q x V or 0.5 x Q^2/C). This represents the work done to charge the capacitor against the growing electric field between its plates.

What is energy density in the field between the plates?

Energy density u = 0.5 x epsilon_0 x epsilon_r x E^2 is the energy stored per unit volume of the field region, it depends only on the field strength and the dielectric, making it a useful measure for comparing energy storage efficiency independent of the specific plate dimensions.

Why does a smaller gap increase the field for the same voltage?

Since E = V/d, for a fixed voltage the field is inversely proportional to the separation distance, halving the gap concentrates the same potential difference over half the distance, doubling the field strength. This is why capacitors with very thin dielectrics can achieve very high fields at modest voltages.

What is relative permittivity (dielectric constant)?

Relative permittivity epsilon_r describes how much more a material can be polarized by an electric field compared to vacuum (epsilon_r = 1). Common dielectrics used in real capacitors, ceramics, polymers, tantalum oxide, have epsilon_r values ranging from around 2 up to several thousand for high-permittivity ceramics.

What limits how high the electric field can be before breakdown?

Every dielectric material has a maximum electric field, its dielectric strength, beyond which it breaks down electrically (arcing or permanent damage). Air breaks down at roughly 3 MV/m at standard conditions, solid dielectrics used in real capacitors typically sustain far higher fields, which is part of why they allow much higher capacitance and voltage ratings in a compact size.

Does plate shape matter for this calculation?

This calculator uses the idealized infinite-parallel-plate approximation, which depends only on total plate area, not shape, for real finite plates the field near the edges (fringing field) differs from the uniform interior field, becoming more significant when the separation is not small compared to the plate dimensions.

What units does this calculator use?

Voltage is in volts, plate separation in millimeters, and plate area in square centimeters. Results are reported in MV/m (electric field), picofarads (capacitance), nanocoulombs (charge), nanojoules or microjoules (energy), and joules per cubic meter (energy density).